Question

What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance

Answer 1

Answer:

New force = 9(initial force)

Explanation:

The force between two charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

Where

d is the original distance

Let d' is the new distance such that, r' = r/3

New force,

$F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\F'=9\times \dfrac{kq_1q_2}{r^2}\\\\F'=9F$

So, the new force becomes 9 times the initial force.