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stealth61 [152]
3 years ago
7

In the past year and a half, Gnarly the dog lost an average of 2/9 pound each month. Today, Gnarly weighs 14 pounds. How much di

d Gnarly weigh a year and a half ago?
Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

Weight before 18 month = 18 pound

Step-by-step explanation:

Given:

Current weight of dog = 14 pound

Weight lose each month = 2/9 pound

Total number of month = 1\frac{1}{2} year = 18 month

Find:

Weight before 18 month

Computation:

Total weight lose = Weight lose each month x Total number of month

Total weight lose = 2/9 x 18

Total weight lose = 4 pound

Weight before 18 month = Current weight of dog + Total weight lose

Weight before 18 month = 14 + 4

Weight before 18 month = 18 pound

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Delicious77 [7]
72 3 plus 62 is 65 plus 7 is 72
6 0
3 years ago
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For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.
iragen [17]

Answer:

-\frac{7}{3}

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

m=\frac{f(b)-f(a)}{b-a}

where

m is the average rate of change

a is the first point

b is the second point

f(a) is the function evaluated at the first point

f(b) is the function evaluated at the second point

We want to know the average rate of change of the function f(x)=0.5^x-6 form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, a=-3 and b=0.

Replacing values

m=\frac{f(b)-f(a)}{b-a}

m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}

m=\frac{1-6-(8-6)}{3}

m=\frac{-5-(2)}{3}

m=\frac{-5-2}{3}

m=\frac{-7}{3}

m=-\frac{7}{3}

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is -\frac{7}{3}

4 0
3 years ago
What is estimate 4.23-2.51
ruslelena [56]
The answer is 1.72 and it would be 2 if u estimated
4 0
3 years ago
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3. E, F and G are collinear points. E is between F and G.
nikdorinn [45]

Answer:

<h2>A. 4 in</h2>

Step-by-step explanation:

Collinear points are points that lies on the same straight line. If the points E, F and G are collinear points, then the three points lies on the same straight line.

If E is between F and G, the FE+EG = FG

EG = FG - FE

Given FE = 3 in and FG = 7 in

On substituting into the expression above to get EG;

EG = 7in - 3in

EG = 4in

Hence the length of EG is 4in

5 0
3 years ago
What is the zero in the quadratic function f(x)= 9x^2-54x-19?
Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is


x=\frac{-b+\sqrt{b^2-4ac} }{2a}.


It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions.  Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}

We will now solve for the plus and the minus.

The plus,,,

x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3

and the minus...

x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...

8 0
4 years ago
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