Please help asap! 7th grade work! Answer all four please!
1 answer:
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Given :
Two similar triangle.
To Find :
The ratio of the area of triangle abc to the area of triangle edc.
Solution :
ΔABC ~ ΔAPQ (AA criterion for similar triangles)
Since both the triangles are similar, using the theorem for areas of similar triangles we have :
Therefore, ratio of area of triangle is 1.4 .
Answer:
Step-by-step explanation:
Given that lines and
are parallel, that means that we can establish some basic angle relationships here.
Since both lines are cut by a transversal, that means all angles formed by that line will be equivalent.
and
are going to be equivalent because they are alternate exterior angles. These are formed by two parallel lines being cut by a transversal, and they will always be equal.
Since we know that both angles are equivalent to each other, we can set the expressions equal to each other to find x.
<em>Here's your equation, by the way.</em>
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We can now solve for x.
Add 33 to both sides:
Subtract 2x from both sides:
Therefore, x = 59.
Hope this helped!
Answer:
Step-by-step explanation:
We want to find the equation of a line parallel to:
And passes through (-5, -5).
Recall that parallel lines must have the same slope.
Since the slope of our old line is 3/5, the slope of our new line must also be 3/5.
So, we know that the slope of our new line is 3/5 and it passes through (-5, -5).
Now, we can use the point-slope form given by:
We will let (-5, -5) be (x₁, y₁). m is the slope or 3/5. Hence:
Simplify:
Distribute:
Subtract 5 from both sides:
And we have our equation.