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3 years ago

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Suppose a 200-mm focal length telephoto lens is being used to photograph mountains 11.5 km away. Part (a) What is image distance

, in meters, for this lens? Part (b) What is the image height, in centimeters, of a 950-m high cliff on one of the mountains?

1 answer:

Nuetrik [128]3 years ago

5 0

This is your answer...Down below

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Which of these would be a good model to demonstrate the fact that the galaxies are moving apart as the universe is expanding?

Sergio [31]

Answer: Option A: The spots on the balloon move away as the balloon is inflated.

one of the scientific models describes the galaxies are moving apart as the universe is expanding. This expansion theory came from the observation of red-shifted spectrum from all the directions indicating that the galaxies are moving away. This can be understood from the inflated balloon. Initially spots can be marked using a colored pen on the balloon.On inflating the balloon, it would be noticed that the spots on the balloon move away. Actually the position of the spots won't change, but the distance between the spots would expand. This is a good model to explain the expanding universe. The galaxies are neither moving in any random direction nor moving forward. So, rest of the options are not good models to explain the theory.

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3 years ago

An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni

Marysya12 [62]

When air is blown into the open pipe,

L = $\frac{nλ}{2}$

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ= $\frac{2L} {n}$

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ= $\frac{(2)*(6)}{4}$ =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= $\frac{c}{λ}$

⇒f= $\frac{344}{3}$

≈115 Hz

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4 years ago

Assume that both the supply of and the demand for a good are relatively price elastic. The imposition of a per-unit excise tax o

sergey [27]

Answer:P:Increase Q:Decrease

Explanation: The price of the product will increase as the imposed per-unit excise tax on the sale of the good. This is true for both Perfectly-elastic and relatively elastic products.

The quantity demanded of the product will decrease as the price of the product increases, this his is true for both Perfectly-elastic and relatively elastic products. It will follow the law of Demand and Supply.

5 0

4 years ago

Read 2 more answers

A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most

alexgriva [62]

Answer:

a) I = 1.44 Kg.m²

b) I = 3.12 Kg.m²

As rarm increases, her moment of inertia will increase.

Explanation:

Given

The skater's mass: M = 64 Kg

Mass of both arms: m = (M/8) = 64 Kg / 2 = 8 Kg

Mass of one arm: = marm = m/2 = 8 Kg / 2 = 4 Kg

Mass of her rest body: Mcyl = M - 2m = 64 Kg - 8 Kg = 56 Kg

rarm = 0.20 m

Rcyl = 0.20 m

Larm = 0.60 m

a) We apply the equation (Using the Steiner Theorem)

I = Icyl + Iarms

I = (Mcyl*Rcyl²/2) + 2*marm*rarm²

I = (56 Kg*(0.20 m)²/2) +2(4 Kg)(0.20 m)²

I = 1.44 Kg.m²

b) Suppose that the center of the mass of her outstretched arm is in the middle, so that the mass of the arm will be at a distance of 50 cm, then

rarm = 0.50 m

We apply the same equation, then

I = Icyl + Iarms

I = (Mcyl*Rcyl²/2) + 2*marm*rarm²

I = (56 Kg*(0.20 m)²/2) +2(4 Kg)(0.50 m)²

I = 3.12 Kg.m²

As rarm increases, her moment of inertia will increase.

8 0

3 years ago

The total mass of the train and its passengers is 750000kg. The train is traveling at a speed of 84m/s. The driver applies the b

fiasKO [112]

Answer:

|F| = 393750 N

Explanation:

Given that,

Total mass of the train, m = 750000 kg

Initial speed, u = 84 m/s

Final speed, v = 42 m/s

Time, t = 80 s

We need to find the net force acting on the train. The formula for force is given by :

F = ma

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{750000\times (42-84)}{80}\\\\F=-393750\ N$

So, the magnitude of net force is 393750 N.

4 0

3 years ago