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puteri [66]
3 years ago
8

Were discovered by James Chadwick and Carl Anderson.

Physics
2 answers:
Radda [10]3 years ago
6 0

Answer:

1 is a great answer for this question

Kryger [21]3 years ago
4 0
I believe number one
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An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
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Answer:

vertical distance, s = 0.16 meters

Explanation:

It is given that,

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.

Dashboard is placed at a distance of 2.7 meters.

Calculating time from velocity and distance i.e. t=\dfrac{d}{s}=\dfrac{2.7}{15}\ s=0.18\ s

Using second equation of motion for finding vertical distance :

s=ut+0.5gt^2

Here, u = 0 (for vertical velocity )

s=0.5gt^2  

s=0.5\times 10\times (0.18)^2        

s = 0.162 meters

or s = 0.16 meters

Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.

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