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2 years ago

Find the 10th term of the geometric sequence show below

Mathematics

1 answer:

andrey2020 [161]2 years ago

4 0

Answer:

-19,6830x^26

Step-by-step explanation:

The nth term of a geometric sequence is expressed as;

Tn -= ar^n-1

a is the first term

is the number of terms

r is the common ratio

Given

a = -10x^8

r = 30x^10/-10x^8 = -3x^2

n = 10

Substitute

a10 = (-10x^8)(-3x^2)^10-1

a10 = (-10x^8)(-3x^2)^9

a10 = -10x^8)(19,683)x^18

a10 = -19,6830x^26

Hence the tenth term is -19,6830x^26

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Then,

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For $v(0)=v_0$ , then

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For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

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2 years ago

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Answer:

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Step-by-step explanation:

For this case we have the following interval for the difference between Silver Queen - Country Gentlemen:

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We can conclude that the difference between the two means are between -0.223 and 0.988.

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2 years ago

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krok68 [10]

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So your answer is 3/2x.

Hope this helps!

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