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IrinaVladis [17]
3 years ago
6

Please help me please thank you

Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

x = 15

Step-by-step explanation:

angles 2 and 4 are supplementary so they add up to 180

2x + 10 + 4x + 80 = 180

6x + 90 = 180

6x = 90

x = 15

mariarad [96]3 years ago
7 0

Answer:

x=15

Step-by-step explanation:

Angles 2 and 4 are same-side interior angles. This means that if they are supplementary angles, then the lines A and B are parallel.

Supplementary angles, when added together, will equal a total of 180°. Set up an equation in which the angles are added and are equal to 180:

(2x+10)+(4x+80)=180

Solve for x. Remove the parentheses and combine like terms:

2x+10+4x+80=180\\\\2x+4x+10+80=180\\\\6x+90=180

Work to isolate the variable, x. Subtract 90 from both sides:

6x+90-90=180-90\\\\6x=90

Isolate x. Divide both sides by 6:

\frac{6x}{6}=\frac{90}{6}  \\\\x=15

The value of x is 15.

:Done

If you want to check your work, insert the value of x into the angles, and add them. If the answer is 180, then the value of x is true:

2x+10\\\\2(15)+10\\\\30+10\\\\40

∠2=40

4x+80\\\\4(15)+80\\\\60+80\\\\140

∠4=140

∠2+∠4=180

40+140=180

The value of x is true.

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A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
2 years ago
(15y^0 x^-3 z^2/ 3x^3 y^7 z^1/2)^2
ArbitrLikvidat [17]
Hello! For this you are just going to do this step by step, and remember to use PEMDAS. That is the order in which you should do the math. The abbreviation stands for  Parenthesis, exponents, multiplication, division, addition and subtraction. So lets get started!
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Hope this helps!! If you need any more help or further explanation just let me know!! :)
 

6 0
3 years ago
The product of two numbers is 161 , one of number is 7,find the other number. ​
Diano4ka-milaya [45]

let the other number be " n "

now, according to above condition :

  • n × 7 = 161

  • n = 161 ÷ 7

  • n = 23

therefore, the other number would be 23.

4 0
3 years ago
In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa
MakcuM [25]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

Step-by-step explanation:

Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

X_{2}=9 represent the number of renters who would buy the security system

n_{1}=140 sample 1

n_{2}=60 sample 2

p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

p_{2}=\frac{9}{60}= 0.15 represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

6 0
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spayn [35]
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7 0
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