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Arisa [49]
3 years ago
9

What happens to the do Broglle wavelength of an electron If its momentum ls doubled?​

Chemistry
1 answer:
algol133 years ago
8 0
Answer:
The De Broglie wavelength decreases when the momentum increases
Explanation:
The De Broglie wavelength of a particle (or any object) is given by

where
h is the Planck constant
p is the momentum of the object
As we can see, the wavelength is inversely proportional to the momentum of the object: therefore we can say that, if the momentum increases, the De Broglie wavelength will decrease.
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Calculate the volume of 4.00 molar NaOH solution required to prepare 100 mL of a 0.500 molar solution of NaOH.
Kazeer [188]

Answer:

The answer to your question is V₁ = 12.5 ml

Explanation:

Data

Volume = V₁?

[NaOH] = C₁ = 4.0 M

Volume 2 = V₂ = 100 ml

[NaOH] = C₂ = 0.5 M

Formula of dilution

                             V₁C₁   =  V₂C₂

Solve for V₁ (original solution)

                                 V₁ = \frac{V2C2}{C1}

Substitution

                                V₁ = \frac{(0.5)(100)}{4}

Simplification

                                V₁ = \frac{50}{4}

Result

                                V₁ = 12.5 ml

7 0
3 years ago
What's the pH of a solution with a concentration of hydronium ions of 5.29x10^-10?
romanna [79]
C. 5.29 should be the answer
7 0
3 years ago
Read 2 more answers
Propose a 3-step reaction for the conversion of cyclopentene to propanedioic acid
Gnom [1K]

I
don't know because this is the question which I never heard

6 0
3 years ago
Explain how an automobile air bag protects the people in the car from being hurt as a result of impact
liraira [26]
The quick deployment of the bag which I think is quite similar to a cushion and a balloon. It holds your head/face away from any hard surfaces. Although it does not protect your legs or other extremities that are out of the bags range.
5 0
3 years ago
Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = 165°C

Depression in freezing point = \Delta T_f=?

\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

m=\frac{14^oC}{1\times 40^oC kg/mol}=0.35 mol/kg

The molality of isoborneol in camphor is 0.53 mol/kg.

8 0
3 years ago
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