Answer:
<h3>The answer is 8.00 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>8.00 moles</h3>
Hope this helps you
Answer:
By weight they have the same mass, but the number of atoms is different
Explanation:
Answer:
C
Explanation:
D: Wrong! going to bed early is a learned behavior. If someone wakes you up early enough times, you will get up early.
B: Being musical is possible that you will inherit such an ability, but I think you are intended not to give B as an answer.
A: You can learn to like favorite foods because they are being served. Favorite foods are a craving. It is like B. It might be, but I don't think you are intended to answer it.
C: is definitely an inherited quality.
When sodium phosphate reacts with sulfuric acid, forming sodium sulfate and phosphoric acid, the stoichiometric coefficient for sulfuric acid in the balanced chemical equation is 3.
In every balanced chemical equation, the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side. The stoichiometric coefficient is the number written in front of each reactants and products that tells how many moles of each are needed in the reaction.
The chemical equation for the given reaction is:
+
=
+ 
Put the necessary stoichiometric coefficient to balance each element.
Balancing Na:
+
=
+ 
Balancing P:
+
=
+ 
Balancing S:
+
=
+ 
Notice that H and O are already balanced.
Hence, the balanced chemical equation for the reaction is:
+
=
+ 
where 3 is the stoichiometric coefficient of sulfuric acid,
.
Learn more about stoichiometric coefficient here: brainly.com/question/6666875
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Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m