Each description is dragged into the most appropriate bin.
Explanation:
We assume that
is represented by A and
is represented by B respectively.
According to Wilke Chang equation as follows.
![D_{AB} = \frac{7.4 \times 10^{-8} \times (\phi_{B} M_{B})^{1/2} \times T}{V^{0.6}_{A} \times \mu_{B}}](https://tex.z-dn.net/?f=D_%7BAB%7D%20%3D%20%5Cfrac%7B7.4%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%28%5Cphi_%7BB%7D%20M_%7BB%7D%29%5E%7B1%2F2%7D%20%5Ctimes%20T%7D%7BV%5E%7B0.6%7D_%7BA%7D%20%5Ctimes%20%5Cmu_%7BB%7D%7D)
![D_{O_{2} - H_{2}O} = \frac{7.4 \times 10^{-8} \times (\phi_{H_{2}O} M_{H_{2}O})^{1/2} \times T}{V^{0.6}_{O_{2}} \times \mu_{H_{2}O}}](https://tex.z-dn.net/?f=D_%7BO_%7B2%7D%20-%20H_%7B2%7DO%7D%20%3D%20%5Cfrac%7B7.4%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%28%5Cphi_%7BH_%7B2%7DO%7D%20M_%7BH_%7B2%7DO%7D%29%5E%7B1%2F2%7D%20%5Ctimes%20T%7D%7BV%5E%7B0.6%7D_%7BO_%7B2%7D%7D%20%5Ctimes%20%5Cmu_%7BH_%7B2%7DO%7D%7D)
where, T = absolute temperature = (273 + 37)K = 310 K
= an association parameter for solvent water = 2.26
= Molecular weight of water = 18 g/mol
= viscosity of water (in centipoise) = 0.62 centipoise
= the molar volume of oxygen = 25.6 ![cm^{3}/g mol](https://tex.z-dn.net/?f=cm%5E%7B3%7D%2Fg%20mol)
Hence, putting the given values into the above formula as follows.
![D_{O_{2} - H_{2}O} = \frac{7.4 \times 10^{-8} \times (\phi_{H_{2}O} M_{H_{2}O})^{1/2} \times T}{V^{0.6}_{O_{2}} \times \mu_{H_{2}O}}](https://tex.z-dn.net/?f=D_%7BO_%7B2%7D%20-%20H_%7B2%7DO%7D%20%3D%20%5Cfrac%7B7.4%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%28%5Cphi_%7BH_%7B2%7DO%7D%20M_%7BH_%7B2%7DO%7D%29%5E%7B1%2F2%7D%20%5Ctimes%20T%7D%7BV%5E%7B0.6%7D_%7BO_%7B2%7D%7D%20%5Ctimes%20%5Cmu_%7BH_%7B2%7DO%7D%7D)
= ![\frac{7.4 \times 10^{-8} \times (2.26 \times 18)^{1/2} \times 310 K}{(25.6)^{0.6}_{O_{2}} \times 0.692}](https://tex.z-dn.net/?f=%5Cfrac%7B7.4%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%282.26%20%5Ctimes%2018%29%5E%7B1%2F2%7D%20%5Ctimes%20310%20K%7D%7B%2825.6%29%5E%7B0.6%7D_%7BO_%7B2%7D%7D%20%5Ctimes%200.692%7D)
= ![3021.7 \times 10^{-8} cm^{2}/s](https://tex.z-dn.net/?f=3021.7%20%5Ctimes%2010%5E%7B-8%7D%20cm%5E%7B2%7D%2Fs)
Thus, we can conclude that the diffusion of
in water by the Wilke-Chang correlation at
.
Answer:
0.404 moles Na⁺ and 0.404 moles Cl⁻
Explanation:
In the solution you have 23.6g of NaCl. As molar mass of NaCl is 58.44g/mol. Moles you have present are:
23.6g NaCl × (1mol / 58.44g) = <em>0.404 moles of NaCl</em>
As you can see in the formula, each mole of NaCl contains 1 mole of Na⁺ and 1 mole of Cl⁻. Thus, moles of each ion are:
<em>0.404 moles Na⁺ and 0.404 moles Cl⁻</em>
Answer:
pH = 10.4
Explanation:
pH = -log [H⁺] = -log(4.1 x 10⁻¹¹) = -(-10.4) = 10.4
Sulfur is a non-metal, being in the third period, in group 6