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timofeeve [1]
3 years ago
15

What will be the pressure of 2.00 mol of an ideal gas at a temperature of 20.5 degrees Celsius and a volume of 62.3L?

Chemistry
1 answer:
erastova [34]3 years ago
7 0

.774atm

First, look at what you have and look at the equations you can use to solve this problem. The best equation would be PV=nRT.

P being pressure, V being volume, n being moles, R being the gas constant, and T being temperature.

Before you start doing any of the math, make sure of two things. Since you're looking for pressure, you'll need a gas constant. When I did the problem, I used the gas constant of atm or atmospheres which is .0821.

Also! Remember to always convert celsius into kelvin, to do this, add 273 to the given celsius degree. After this is all set and done, your equation should look like this:

P = \frac{2 x .0821 x 293.5}{62.3}

The reason that the equation is divided by the volume is due to the fact that you need to isolate the variable or pressure.

Multiply everything on the top and divide by the bottom and you should receive the final answer of .774atm.

Hope this helps!

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Answer:

true

Explanation:

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The picture shows a contractile vacuole of a unicellular freshwater organism. The contractile vacuole regulates the flow of wate
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Answer:

A.The concentration of water is greater outside the cell than inside the cell.

Explanation:

The contractile vacuole of certain organisms functions to regulate water flow in and out of the cell. It does this by storing excess water that comes into the cell. In the case of this organism with a filled up contractile vacuole, it means water is flowing into the cell.

Naturally, water will flow into a living cell when an osmotic gradient i.e. difference in concemtration, has been created between intracellular and extracellular solutions. Osmosis involves movement of substances from a region of high water concentration to a region of low water concentration. This means that if water is flowing into the cell, which is stored by the contractile vacuole, the concentration of water must be greater outside the cell than inside.

6 0
3 years ago
Which one of the following items does NOT characterize a reducing agent? a. A reducing agent loses electrons. b. A reducing agen
Ad libitum [116K]

Answer: D

Explanation:

A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.

Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.

For B, this is true as we have established this already.

C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.

D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.

4 0
3 years ago
Could the structures below undergo a Fischer esterification reaction? Reaction scheme of benzoic acid and thionyl chloride to fo
Romashka-Z-Leto [24]

Answer:

The correct answer is the first option. No, the structures above cannot undergo a Fischer esterification reaction to form an ester.

Explanation:

The reaction that will take place can be found in the attached file. The reaction does not require any catalyst and it cannot undergo a Fischer esterification reaction to form an ester.

4 0
3 years ago
You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid
nataly862011 [7]

Answer:

V_1=9.63mL

Explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

n_1=n_2\\

That in terms of molarities and volumes is:

M_1V_1=M_2V_2

Whereas M_1 is the initial molarity (3.00 M) of the stock solution, M_2 the molarity of the diluted solution (0.289 M), V_1 the aliquot of the stock (concentrated) solution and V_2 the volume of the diluted solution (100 mL), thus, we compute V_1 as required:

V_1=\frac{M_2V_2}{M_1} =\frac{0.289M*100mL}{3.00M} \\\\V_1=9.63mL

Best regards.

7 0
3 years ago
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