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n200080 [17]
2 years ago
12

PLSSSS ANSWER!!!!!!!!!!!!!

Chemistry
2 answers:
saveliy_v [14]2 years ago
5 0
The answer is D hhshhhhshhnwnhwnhwnwhwhns
Jobisdone [24]2 years ago
5 0

Answer:

D

Explanation:

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Jenna built the electrical circuit seen here. What would happen to the electrical energy if Jenna removed one of the clips on th
otez555 [7]

Answer: Option (D) is the correct answer.

Explanation:

An electric circuit works well when all the connections are complete but if any of the connections in the circuit is loose or disconnected then it is possible that current will not flow from the circuit.

Therefore, when Jenna removed one of the clips on the battery then circuit becomes incomplete and as a result there will no flow of current.

Thus, we can conclude that the electrical energy would stop because the circuit is incomplete.

6 0
2 years ago
What property of argon is uses in light bulbs?
otez555 [7]
<span>The filament of the light bulb will get very hot. This will encourage a chemical reaction with most gases that are surrounding that filament - and the result is that the filament burns out. If the filament is in air, it combines with the carbon of carbon dioxide in the air, and the filament disintegrates. But argon is an inert gas - almost nothing reacts with it. So the filament takes a very long time (theoretically infinity) to burn out. But the bulb cannot contain 100% argon: 99.9% is typical; the remaining 0.1% being air. The bulb manufacturers can control the 'life' of a bulb, based on that principle: they do not want their bulbs to last forever!</span>
8 0
3 years ago
Read 2 more answers
What is the specific latent heat of a fussion for a substance that takes 550 kj to melt 14 kg at 262 k?
Lina20 [59]

The latent heat is correlated with energy as follows:

Q = mL

550 * 103 = 14 * 103 * L

L = 39.285 J /g

Thus, latent heat of the substance is 39.285 j /g

7 0
3 years ago
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
Read 2 more answers
What are compounds that react with acids and bases to make certain colors?
finlep [7]
Those would be called indicators , simply google them and you should find many. I'll leave some examples "bromophenol blue"  "Methyl red" and "phenol red".
4 0
3 years ago
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