Answer:
the answer will be lithium bromide + sodium
Explanation:
because displace sodium from bromine there by liberating sodium as an element in the product side
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Answer: any answer choices
Explanation:
When a non volatile solute is added to a solvent, the vapor pressure of the solvent will decrease.
Vapor pressure is a colligative property. Which means that it will be affected by the number of particles of solute.
The relationship between the concentration of the solute and the vapor pressure is given by Roult's Law
ΔP = Xsolute * P, where ΔP is vapor pressure lowering, Xsolute is the molar fractionof the solute, and P is the vapor pressure of the solvent.
Then lets find Xsolute
X solute = # moles solute / # moles solution
# moles solute = 75.0 grams / molar mass
molar mass of C12H22O11 = 12*12g/mol + 22*1g/mol + 11*16g/mol = 342 g/mol
# moles solute = 75.0/342 mol = 0.219 mol
# moles of solvent = grams of solvent / molar mass of solvent
# moles of solvent = 180 grams /18 g/mol = 10 mols
Xsolute = 0.219 mol solute / (10 + 0.219) mol solution =0.0215
ΔP = 0.0215*26.7 torr = 0.57 torr
Answer= 0.57 torr
Haha ironically I had this problem not too long ago, I hope by this we will both be better students. Everyone just needs practice. Ok stop to pep talk and lets go. I'll try to go step by step.
<span>So basically since this is a balanced equation, the ratios of mols of the elements are equal, atom wise. </span>
<span>So you notice they give you Br2 is 1.0 kg (1000g) and that means there are 2 mols of Br2. And its asking for Cl2, (on the left) it also has 2 mols. </span>
<span>Then you can start from 1000g Br2 and multiply with 2 mol Br2 and 159.8g Br2 on the bottom. The 159 8 is the actual grams per mol. Then when you write this down, continue multipying with the next fraction. </span>
<span>Since you know the molar mass of Cl2 is 70.4 and you know theres 2 mols, you can say that 2 mols of Br2 = 2 mols of Cl2 so you should be able to multiple 2 mol Br2 / 159.8g Br2 with 70.4 g Cl2 / 2 mol Cl2. Bam the mols cancel out and you have the grams for Cl2. Multiple all that out and you should get 443g Cl2. Notice how the beginning question gives 2 significant figures, so technically 440g Cl2 is more of an exact number.</span>
