Answer:
candice
Step-by-step explanation:
Answer:
z= 125 because they are congruent and y = 55 because they are congruent
I hope this is good enough:
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
To do this you need to multiply 1,800 by ten. you will get 18,000. Then you need to divide this by 1000 to get 18. 18 1000's will equal ten 1800
Answer:
m = 9
Step-by-step explanation:
8/12 = 6/m
8m = 72
m = 9
