3 years ago

Is (1,8), (2,12), (3,16) (4,20) a function?

1 answer:

8 0

Yes it is a function. As x increases by one, y constantly increases by 4. The function would me y=4x+4

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beks73 [17]

It should be 124200................................

i apologize for the period spam. character limit

7 0

3 years ago

lyudmila [28]

Answer:

Step-by-step explanation:

Given that

$r(t) = (t,t,e^t)$

To find tangent, normal and binormal vectors at (0,0,1)

i) Tangent vector

$r'(t) = (1,1,e^t)\\$

At the particular point, r'(t) = (1,1,e)

Tangent vector = $\frac{r'(t)}{||r'(t)||} \\=\frac{(1,1,e)}{\sqrt{1+1+e^2} } \\=\frac{(1,1,e)}{\sqrt{2+e^2} }$

ii) Normal vector

T'(t) = $(0,0,e^t)\\$

At that point T'(t) = (0,0,e)/e = (0,0,1)

iii) Binormal

B(t) = TX N

= $\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)$

8 0

4 years ago

Dahasolnce [82]

The answer is true because it is the same

6 0

3 years ago

marissa [1.9K]

Go off bestie yuhhhh

6 0

3 years ago

Alenkasestr [34]

Your answer would be 5 1/4

7 0

3 years ago