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gladu [14]
3 years ago
7

Molecules of ice have less mass than molecules of water. True or False

Chemistry
1 answer:
Semenov [28]3 years ago
3 0

Answer:

Explanation:

water has greater density than ice. so true

You might be interested in
How many moles of sodium sulfate will be formed if you start with 3.7 moles of sodium hydroxide?
Andrew [12]

First check it's balanced or not

On both sides

  • Na=2
  • O=6
  • H=4
  • S=1

Its balanced

  • 2 mol NaOH produces 1 mol Na_2SO_4
  • 1 mol NaOH produces 0.5mol Na_2SO_4

3.7 mol produces=3.7(0.5)=1.850=1.8mol Na_2SO_4

3 0
2 years ago
1. In 1996 a meteor crashed into the Earth near Steelsville, Ontario. The resulting meteorite was found to contain 5,790 g of Mo
wlad13 [49]

Answer:

6.38×10²¹ molecules

Explanation:

Formula for molybdenum chloride is:

Mo₂Cl₁₀

Molar mass is : (Molar mass for Mo) . 2 + (Molar mass for Cl) . 10

95.94  . 2 + 35.45  . 10 = 546.38 g/mol

We determine moles that are contained in 5.790 g of Mo₂Cl₁₀

5.790 g . 1 mol /546.38 g = 0.0106 moles

We count the molecules:  0.0106 mol . 6.02×10²³ molecules / mol =

6.38×10²¹ molecules

Remember that 6.02×10²³ is also called Avogadro's number (NA) which is the number of particles of anything, that are contained in 1 mol.

4 0
3 years ago
If I have 340 mL of a 1.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?
ipn [44]

Answer:

0.5667 M ≅ 0.57 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

It can be expressed as:

(MV) before dilution = (MV) after dilution.

M before dilution = 1.5 M, V before dilution = 340 mL.

M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.

∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.

5 0
2 years ago
Can someone help me?
elena-s [515]
It’s will decrease I have to make it 20 characters but it’s decrease
4 0
3 years ago
Read 2 more answers
The use of phenol (carbolic acid) as a wound disinfectant was first practiced by:
uranmaximum [27]

Answer:

The use of phenol (carbolic acid) as a wound disinfectant was first practiced by Lister. The correct option is E

Explanation:

Phenol( carbolic acid) is an aromatic organic compound. It has the following properties:

- it's soluble in water

- it's a weak acid and

- highly reactive toward electrophilic aromatic substitution

In Medical field, phenol was first used as an antiseptic by Joseph Lister.Joseph Lister was a student at University College London under Robert Liston, later rising to the rank of Surgeon at Glasgow Royal Infirmary. He believed that patients who passed through surgery, died due to infections caused by microorganisms.He theorized that if germs could be killed or prevented, no infection would occur. Lister reasoned that a chemical could be used to destroy the micro-organisms that cause infection. He made use of the carbolic acid by soaking a clean cloth in them, and placing it over the surgical wounds of patients.

8 0
3 years ago
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