Hey there!:
Molar mass NaCl = 58.44 g/mol
Number of moles:
n = mass of solute / molar mass
n = 15.6 / 58.44
n = <span>0.2669 moles of NaCl
hope this helps!</span>
Because group 1a and 2a are most reactive due to their least number of electrons in their outmost shell compared to group 8a(18)
The molarity of the stock Mn²⁺ ions is 0.0288 M
Based on the dilution formula;
- The molarity of A is 0.00144 M
- The molarity of B is 0.0000576 M
- The molarity of C is 0.000001152 M
<h3>What is the molarity of a solution?</h3>
The molarity of a solution is the number of moles of a solute dissolved in a given volume of solution in liters.
- Molarity = number of moles/volume
The molarity of the stock solution is:
moles of Mn²⁺ ions = mass / molar mass
molar mass of Mn²⁺ ions = 55.0 g/mol
moles of Mn²⁺ ions = 1.584 / 55
moles of Mn²⁺ ions = 0.0288 moles
molarity of Mn²⁺ ions = 0.0288 / 1
molarity of Mn²⁺ ions = 0.0288 M
The dilution formula is used to determine the molarities of A, B, and C.
C₁V₁ = C₂V₂
C₂ = C₁V₁ / V₂
Where;
- C₁ = initial molarity
- V₁ = initial volume
- C₂ = final molarity
- V₂ = final volume
Molarity of A = 50 * 0.0288 / 1000
Molarity of A = 0.00144 M
Molarity of B = 10 * 0.00144 / 250
Molarity of B = 0.0000576 M
Molarity of C = 10 * 0.0000576 / 500
Molarity of C = 0.000001152 M
Learn more about molarity at: brainly.com/question/17138838
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<h3>
Answer:</h3>
72.19 g HCl
<h3>
Explanation:</h3>
We are given the reaction between hydrogen gas and chlorine gas as;
H₂(g) + Cl₂(g) → 2HCl(g)
Mass of hydrogen gas that reacts is 2 g
We are required to determine the amount of HCl produced
<h3>Step 1: Determine the number of moles of H₂ used </h3>
Moles = Mass ÷ molar mass
Molar mass of Hydrogen gas = 2.02 g/mol
Thus;
Moles = 2 g ÷ 2.02 g/mol
= 0.99 moles
<h3>Step 2: Moles of HCl produced </h3>
From the reaction equation, 1 mole of hydrogen gas reacts to produce 2 moles of HCl
Therefore, the mole ratio of H₂ : HCl = 1 : 2
Thus, moles of HCl = 0.99 moles × 2
= 1.98 moles
<h3>Step 3: Mass of HCl produced </h3>
To calculate mass we multiply the number of moles by molar mass
Molar mass of HCl =36.46 g/mol
Therefore;
Mass of HCl = 36.46 g/mol × 1.98 moles
= 72.19 g
Thus, the amount of HCl produced during the reaction is 72.19 g
