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faltersainse [42]
3 years ago
11

Which of the following enzymes breaks down the "glue" that holds cells together?

Chemistry
1 answer:
sdas [7]3 years ago
3 0

Answer:

1

Explanation:

Hyaluronidase is an enzyme that is naturally found in the body that breaks down hyaluronic acid. Hyaluronic acid is considered the glue that holds cells together.

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1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th
MaRussiya [10]

Answer:

1. \rho=8.06g/cm^3

2. H=10cm

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

V=21.4mL-18.3mL=3.1mL

Thus, the density turns out:

\rho=\frac{m}{V}=\frac{25g}{3.1cm^3}  \\\\\rho=8.06g/cm^3

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3

Moreover, as the volume is also defined in terms of width, height and length:

V=W*H*L

The height is computed to be:

H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm

Best regards.

3 0
3 years ago
To reduce 16 ounces of a 25% solution of antiseptic to a 10% solution, how much distilled water should a nurse add?
NemiM [27]
<span>Let x = amt of distilled water
:
A simple equation
.25(16) = .10(x+16)
4 = .10x + 1.6

4 - 1.6 = .1x
2.4 = .1x
x = 2.4/0.1
x = 24 oz of distilled water
:
:
Prove this by seeing the amt of antiseptic is the same (only the % changes)
.25(16) = .10(24+16)
4 = .1(40)


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
8 0
3 years ago
Read 2 more answers
Which of the following is NOT a unit used to measure temperature?
dalvyx [7]
Watt stands for power that is energy per unit time
7 0
3 years ago
A gamma ray primarily consists of pure energy and no mass. TRUE or FALSE
myrzilka [38]
This statement is true. 
6 0
3 years ago
Read 2 more answers
Draw all four products obtained when 2-ethyl-3-methyl-1,3-cyclohexadiene is treated with HBr at room temperature and show the me
LenKa [72]

Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

5 0
3 years ago
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