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Flauer [41]
2 years ago
8

Density is d= m/vol. If a material has a mass of 65.5 g and a volume of 32.5 ml, it has a density of

Chemistry
1 answer:
ryzh [129]2 years ago
8 0

Using the given formula, the density of the material is 2.015 g/mL

<h3>Calculating Density </h3>

From the question, we are to determine the density of the material

From the given formula

Density = Mass / Volume

And from the given information,

Mass = 65.5 g

and volume = 32.5 mL

Putting the parameters into the equation,

Density = 65.5/32.5

Density = 2.015 g/mL

Hence, the density of the material is 2.015 g/mL.

Learn more on Calculating density here: brainly.com/question/24772401

#SPJ1

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The solar wind is a stream of charged particles released from the upper atmosphere of the Sun, called the corona. ... Its particles can escape the Sun's gravity because of their high energy resulting from the high temperature of the corona, which in turn is a result of the coronal magnetic field.

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If a young girl learned that it would be 0° C, or 32° F, the next
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Cold

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2 years ago
What is the name given to the ions of the halogens on the periodic table?
WARRIOR [948]

Answer:

halides

Explanation:

This is one electron away from having a full octet of eight electrons, so these elements tend to form anions having -1 charges, known as halides: fluoride, F-; chloride, Cl-, bromide, Br-, and iodide, I-. In combination with other nonmetals, the halogens form compounds through covalent bonding.

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3 years ago
1) Given the balance equation below. Calculate how much Na3PO4 in grams you
juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}

1 mole Na3PO4 = 164 g/mole (Molar mass)

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Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

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100 grams of NaOH is produced from =

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2 years ago
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4. On decreasing temperature of an endothermic reaction: Increases the rate of reaction.

So the answer is increase pressure, decrease temperature, increase concentration will increases the rate of the reaction.

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3 years ago
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