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irga5000 [103]
3 years ago
13

Ronaldo can kick a soccer ball 35 meters per second which is about 80 mph. He kicked the ball from one end of the field to the o

ther. The Field is 110m long. How long does the ball take to get from one end of the field to the other if it traveled at the same speed the entire time?
Mathematics
1 answer:
professor190 [17]3 years ago
3 0

Answer:

t=3.142sec

Step-by-step explanation:

From the question we are told that:

Speed of ball V=35m/s\approx 80 mph

Length of field l=110m

Generally the equation for Time taken t is mathematically given by

 t=m/V

 t=110/35

 t=3.142sec

 t \approx \frac{3.142}{60}

 t \approx 0.05hrs

Therefore it will take the ball to get from one end of the field to the other

t=3.142sec

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What is the y-intercept of the function, represented by the table of values
AleksandrR [38]

Answer:

9

Step-by-step explanation:

The table is given below

\left|\begin{array}{c|cc}x&y\\--&--\\-2&15\\1&6\\2&3\\4&-3\\7&-12\end{array}\right|

We can see that the table represents a linear function since by checking its slope.

Using:

  1. Points (-2,15) and (1,6)
  2. Points (1,6) and (2,3)

Slope =\dfrac{6-15}{1-(-2)} =\dfrac{3-6}{2-1}=-3

Therefore, the values represent a linear function.

A linear equation is of the form y=mx+b

Therefore:

y=-3x+b

Using the points (7,-12)

-12=-3(7)+b\\-12=-21+b\\b=-12+21\\b=9

Therefore, the y-intercept of the function, represented by the table of values is 9.

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3 years ago
Mikey is reading a 604-page book. He read 148 pages last week. If he reads for x hours at 19 pages per hour, which equation repr
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3 years ago
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Rainfall in miami was measured during the month of june and is displayed in the following dot plot
Oksi-84 [34.3K]

Answer:

part A: Mean:6.42 Median:7

Part b: median

Part c: no it’s skewed left and unimodal

Step-by-step explanation:

3 0
3 years ago
Factor f(x) = 4x3 + 15x2 – 24x + 5 into linear factors given that - 5 is a zero of f(x).15f(x) = 4x3 + 15x2 - 24x + 5 =(Factor c
Basile [38]

If x=-5 is a zero, then the first factor of the polynomial would be (x + 5 )

To find the other two factors we can divide the polynomial by the expression (x+5).

Using synthetic division, we have:

-5 I 4 15 -24 5 (Coefficients of the dividend)

I -20 25 -5 (Multiplying each coefficient by the results of the substraction and adding)

-----------------------------------------------------------------------------------

4 -5 1 0 (Coefficients of the quotient)

The result of the division is 4x^2 - 5x + 1. Factoring it, we have:

4x^2 - 4x -x + 1 (Separating -5x into -x and -4x)

4x (x - 1) - (x -1) (Factoring each pair of terms)

(x-1)(4x-1) (Factoring using the common factor)

So the answer would be:

(x + 5 )(x-1)(4x-1)

3 0
1 year ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
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