21
is what I got on my calculator
Haha, part of my final today was about this! Don't worry, I got you!
y=2/3x-4
(the 2/3 is supposed to be a fraction)
T+11 because total would mean add them
Answer:
Required difference = 270/19 km
Step-by-step explanation:
If we consider the AP of distances to be
a, a + r, a + 2r, ..., a + 19r,
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
Given that,
a + 19r = 300 .....(1)
a = 30 ..... (2)
Using (2), from (1), we get
30 + 19r = 300
or, 19r = 300 - 30
or, 19r = 270
or, r = 270/19
Therefore the distance between any two successive location is 270/19 km.
