Answer:
(-2)(100) or 10^2 is 100
Step-by-step explanation:
(x -2)(x+100) =x
3 is the scale factor you would use to dilate Figure A to Figure B.
Answer:
A² - 6A + 11 I = ![\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrix
![A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D)
Calculate A² - 6A + 11 I
![A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%20%3D%20A%2AA%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2A2-3%2A1%262%2A3%2B3%2A4%5C%5C-1%2A2-4%2A1%26-1%2A3%2B4%2A4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D)
![6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]](https://tex.z-dn.net/?f=6A%3D6%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D)
![11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]](https://tex.z-dn.net/?f=11%20I%20%3D%2011%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D)
∴ A² - 6A + 11 I = ![\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Out of 30 students, if you add up 11, 16, and 3, you get 30. Which means there is no remainder and there are no students that did not like either sport.
Answer:
Distance = 110.5 cm
Step-by-step explanation:
It is given that,
The basement floor is at an elevation of −10.5 feet
The second story floor has an elevation of 121 feet.
We need to find the distance between the basement floor and the second story floor.
Distance = -10.5 + 121
= 110.5 feet
So, the distance between the basement floor and the second story floor is 110.5 cm.
