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marishachu [46]
3 years ago
10

Can some help me plizz ​

Physics
1 answer:
ddd [48]3 years ago
7 0
Both will hit the ground at the same time because their initial vertical velocity is the same and they are accelerating downward at the same rate (-9.8 m/s^s). Ball A will travel further because it has a greater horizontal velocity and both balls have a horizontal acceleration of 0. Their horizontal velocity will remain contestant and they will travel for the same amount of time. The if t is constant and the v of ball A is greater then D will be greater in the equation
D (distance) = vt+1/2•a•t^2
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How can an element be identified using its emission spectrum?
posledela
The correct choice is C .

Technically, choice-A is the process involved.  But it's already been done,
and widely published, and the spectrum of every element is easily available. 

For you to take the time and go to the trouble of constructing the spectra
would be like inventing wheels if you want to ride a bicycle. 
4 0
3 years ago
A ball is released at the top of a ramp at t = 0. Which is the speed of the ball at t = 4?
Kruka [31]

Answer:

For uniform acceleration

a = (v2 - v1) /t = 2.5      acceleration is constant 2.5

v2 = 2.5 * 4         v1 = 0 at t = 0

v2 = 2.5 m/s^2 * 4 s = 10 m/s

5 0
3 years ago
The molecular mass of sodium oxide (Na2O) is
tresset_1 [31]
<span>The answer is 62 u. The molecular mass of a molecule (Mr) is the sum of atomic masses (Ar) of its elements. Ar(Na) = 23 u. Ar(O) = 16 u. Therefore, the molecular mass of sodium oxide is 62 u: Mr(Na2O) = 2 * Ar(Na) + Ar(O) = 2 * 23 u + 16 u = 46 + 16 = 62 u.</span>
7 0
4 years ago
3. A car travelling at 20. m/s stops in a distance of 40. m. What is its
KIM [24]

Answer:

It was a joke i was getting the answer

Explanation:

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4 0
3 years ago
By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect
sergejj [24]

Answer:

Weight\ loss=1.6321N

Explanation:

From the question we are told that:

Weight W=85.9kg

Altitude h= 6.33 km

Let

Radius of Earth r=6380km

Gravity g=9.8m/s^2

Generally the equation for Gravity at altitude is mathematically given by

 g_s=9.8(\frac{6380}{6380+6.33})^2

 g_s=9.781m/s^2

Therefore

Weight at sea level

 W_s=9.8*85.9

 W_s=841.82N

Weight at 6.33 altitude

 W_a=9.781*85.9

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Therefore

 Weight loss=W_s-W_b

 Weight loss=841.82-840.2

 Weight loss=1.6321N

3 0
3 years ago
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