Answer:
I think the most interesting 3rd century 3g durga was 5f5
Explanation:
I 50degree and I have not done a good morning mam sushant since I am not pregnant and have no 
 
        
             
        
        
        
In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between the variable is a direct. Having a direct relationship means that the<span> relationship between two numbers or other variables where an increase or decrease in one variable causes the same change to the other variable.</span>
        
             
        
        
        
Answer:
C - 50,000 * 77 * 3 
Explanation:
At the top of the hill the potential energy is E= mgh= (160 kg)(9.81 m s^-2)(30 m)= 47088 
hope it helps ,
<u>help me by marking as brainliest....</u>
 
        
             
        
        
        
Answer : 
Essay on Sound instruments/sound boxes:
Musical instruments also some times called <em>"sound box"</em>,  because the box modifies the sound of an instrument. It also helps in transfer of sound to the surrounding air. 
The box is the open chamber in the body of musical instrument 
The sound box responds more strongly to vibrations at certain frequencies created by playing instrument. This phenomena is known as resonance.
The resonance impacts on the tone quality.
For example <em>xylophone</em>, which is a musical instrument with wooden bars. These wooden bars are arranged similar to the piano. under each bar of the xylophone there is a resonator tube, which amplifies the sound. 
 
        
             
        
        
        
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the  wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If  1.21 m contains  1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.