The answer to this question is true I believe
The angle between the string and the vertical is computed by:
Centripetal acceleration Ac = V²/R = 18²/75 = 4.32 m/s² horizontal
Gravitational acceleration g = 9.8 m/s² down
Θ = arctan(Ac/g)
= arctan (4.32m/s^2 / 9.8 m/s^2)
= 23.79° is the answer.
<span>Since the force is applied at an angle from the
horizontal, we will use the horizontal component of this force in calculating
for the displacements.
From derivation, the Fx is:</span>
Fx = F cos φ
Where:
Fx = is the horizontal component of the force
F = total force
φ =
angle in radian = 37 * pi / 180 = 0.645 rad
Calculating: Fx = 30.0 N * cos(0.645)
Fx = 23.97 N = 24 N
Calculating for Work: W = Fx * d
A. W = 24 N * 15 m = 360 N
B. W = 24 N * 16 m = 384 N
C. W = 24 N * 12 m = 288 N
D. W = 24 N * 14 m = 336 N
Answer:
charge, q = ± 1.1 mC
Given:
Capacitance, 
Voltage, V = 110 V
Solution:
The charge on the capacitor plates can be calculated by using the definition of capacitance as :
q ∝ V
where
q = charge
V = potential difference or Voltage
Therefore,
q = CV
Now, charge, q :
q = 
Therefore, the charge on the positive plate is:
q = + 1.1 mC
the charge on the negative plate is:
q = - 1.1 mC
