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Mariana [72]
4 years ago
9

How do you convert .74 kcal/min to cal/sec

Chemistry
2 answers:
mel-nik [20]4 years ago
6 0

since one kilocalorie per minute converted into calorie per second equals = 16.67 cal/sec<span>1 kcal/min = 16.67 cal/sec</span>

<span>so..74 x16.67=</span>

<span>1233.58</span>

<span>
</span>

fiasKO [112]4 years ago
4 0

Answer : The correct answer is, 12.3358 cal/sec

Explanation :

The conversion used from kilo-calorie/min to calorie/second is:

1 kcal/min = 16.67 cal/sec

As we are given 0.74 kcal/min. Now we have to determine it into cal/sec.

As, 1kcal/min=16.67cal/sec

So, 0.74kcal/min=\frac{0.74kcal/min}{1kcal/min}\times 16.67cal/sec=12.3358cal/sec

Therefore, the correct answer is, 12.3358 cal/sec

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Calculate the boiling point of water if the atmospheric pressure is 630 mmhg
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The boiling point of water can be calculated by the equation:

Where:

P = Pressure in mm Hg

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ΔH= heat of vaporization in kJ/mol

R = Ideal Gas Constant (J/mol-K)

To = normal boiling point in Kelvin

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Our known values are:

P = 630 mm Hg

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ΔH = 40.66 kJ/mol = 40.66×1000 =40660

R = 8.314 J mol⁻¹ K ⁻¹

To = 373 K

Putting these values in the equation,

ln \frac{P_{0}}{P}= \frac{\Delta H}{R}(\frac{1}{T}-\frac{1}{T_{0}})

ln \frac{760}{630}= \frac{40660}{8.314}(\frac{1}{T}-\frac{1}{373})

Solving the equation will give:

T=370K

so, the boiling point of water is 370 K.

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Racecar driver Keimesha was in a race and accelerated from rest to 39 m/s by the time she reached the finish line. Keimesha’s ca
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the acceleration of the racecar is 6.5 m/s²

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The acceleration of the racecar is calculated as;

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