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3 years ago

Which of the following states that submicroscopic particles of all matter are in constant random motion?

1 answer:

4 0

The best and most correct answer among the choices provided by the question is the third choice. A theory stating particles of all matter are in constant random motion would be the kinetic theory. I hope my answer has come to your help. God bless and have a nice day ahead!

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Does the result of the calculation in question 3 justify your original assumption that all of the SCN^- is in the form of FeNCS^

Naddik [55]

Fe 3+ + SCN- --> FeSCN 2+

.......Fe 3+ .......SCN-.........FeSCN 2+ 
I.......0.04..........0.001.............. 
C........-x...............-x............. 
E.....0.04-x.....0.001-x...........x 

Keq = 203.4 = x / (0.04-x)(0.001-x) 
203.4 = x / (x^2 - 0.041x + 4x10^-5) 
203.4x^2 - 8.34x + 0.00094 = x 
203.4x^2 - 9.34x + 0.00094 = 0 
x = -0.0001M or 0.0458M 
so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+

5 0

3 years ago

He free energy of a gas depends on __________. (select all correct answers) partial pressure of the gas van der waals constant f

Black_prince [1.1K]

Viscosity of the gas

4 0

3 years ago

HELP ASAP!!!

givi [52]

This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

I looked this up but hope it helps!

4 0

3 years ago

A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and

lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

$F_{solution}$ = mass of solvent + mass of oil (i.e A+C)

Feed Phase:

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

= 25kg

Mass ratio of oil to solution $Y_{F}$ = $\frac{Mass C}{Mass (A+C)}$

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane in feed = 25 × 0.9 =22.5kg + 2.5 =25kg

therefore $Y_{F}$ = $\frac{2.5}{25}$

= 0.1

mass ratio of solid to solution $Y_{A}$ = $\frac{Mass A}{Mass (A+C)}=[tex]\frac{75}{25}$

Solvent Phase:

C= Mass of oil= 0(kg)

A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

solvent= 100kg

Underflow:

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = $\frac{mass B}{mass(A+C)}$

solution in underflow E₁ = Mass (A+C)

Overflow:

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75= E₁ × N₁

75 = E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

5 0

3 years ago

which type of chemical bond would be formed between two elements having electron configuration of 1s2 2s2 2p6 3s2 and 1s2 2s2 2p

OLga [1]

The electron configuration
1
s
2
2
s
2
2
p
6
3
s
2
3
p
2
is the element Silicon.
The key to deciphering this is to look at the last bit of information of the electron configuration
3
p
2
.
The '3' informs us that the element is in the 3rd Energy Level or row of the periodic table. The 'p' tells us that the element is found in the p-block which are all of the Groups to the right of the transition metals, columns 13-18. The superscript '2' tells us that the element is found in the 2nd column of the p-block Group 14.

7 0

3 years ago