Hello!
The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³
A 12 cm cone with a dome on top of it that has an 8 cm diameter
Data: (Cone)
h (height) = 12 cm
r (radius) = 4 cm (The diameter is 8 being twice the radius)
Adopting: 
V (volume) = ?
Solving: (Cone volume)




Note: Now, let's find the volume of a hemisphere.
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 4 cm
Adopting: 
If: We know that the volume of a sphere is
, but we have a hemisphere, so the formula will be half the volume of the hemisphere 
Formula: (Volume of the hemisphere)

Solving:





Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)
Volume of the figure = cone volume + hemisphere volume
Volume of the figure = 200.96 cm³ + 133.97 cm³

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I Hope this helps, greetings ... Dexteright02! =)
< and > means greater than or less than**
Anything that is closer to the positive side of the number line is considered greater.
So,
All are true.
Answer:
The correct answer is: A = 1/2 bh V = integral A(x) from [-r, r].
Step-by-step explanation:
x^2 +y^2 = r^2 A = 1/2 bh b = 2y = 2sqrt[r^2 - x^2] so that gives A = 1/2 [ 2sqrt(r^2 - x^2)]h which gives A = sqrt[r^2 - x^2]h
The correct answer for the question that is being presented above is this one: "<span>A) The temperature only adds 14 to the damage index." </span>Sven investigates the amount of damage to the head gaskets on the trucks in his fleet and find that the damage index depends on the ambient temperature.
You ever get the answers I need them