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Maurinko [17]
3 years ago
14

This career applies mathematical and theoretical knowledge in order to compare and produce computational solutions.

Computers and Technology
2 answers:
IgorC [24]3 years ago
6 0
My answer would be cyber security.
ipn [44]3 years ago
4 0

Answer:

Why does love.com redirect to Verizon.

Explanation:

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apple because apple is always better

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3 years ago
Implement the RC4 stream cipher in C++. User should be able to enter any key that is 5 bytes to 32 bytes long. Be sure to discar
gladu [14]

Answer:

Explanation:

#include <iostream>

#include <string>

#include<vector>

using namespace std;  

vector<int> permute(vector<int>, vector<int>);

string encrypt(vector<int>s1 , vector<int> t1, string p);

string decrypt(vector<int>s1, vector<int> t1, string p);

int main() {

  string plaintext = "cryptology";

  string plaintext2 = "RC4";

  vector<int> S(256);

  vector<int> T(256);

  int key[] = { 1,2,3,6 };

  int key2[] = { 5,7,8,9 };

  int tmp = 0;

  for (int i = 0; i < 256;i++) {

      S[i] = i;

      T[i] = key[( i % (sizeof(key)/sizeof(*key)) )];

  }

  S = permute(S, T);

  for (int i = 0; i < 256 ;i++) {

      cout << S[i] << " ";

      if ((i + 1) % 16 == 0)

          cout << endl;

  }

  cout << endl;

  string p = encrypt(S, T, plaintext);

  cout << "Message: " << plaintext << endl;

  cout << "Encrypted Message: " << " " << p << endl;

  cout << "Decrypted Message: " << decrypt(S, T, p) << endl << endl;

  tmp = 0;

  for (int i = 0; i < 256;i++) {

      S[i] = i;

      T[i] = key2[(i % (sizeof(key) / sizeof(*key)))];

  }

  S = permute(S, T);

  for (int i = 0; i < 256;i++) {

      cout << S[i] << " ";

      if ((i + 1) % 16 == 0)

          cout << endl;

  }  

  cout << endl;

  p = encrypt(S, T, plaintext2);

  cout << "Message: " << plaintext2 << endl;

  cout << "Encrypted Msg: " << p << endl;

  cout << "Decrypted Msg: "<<decrypt(S, T, p) << endl << endl;

  return 0;

}

string decrypt(vector<int>s1, vector<int> t1, string p) {

  int i = 0;

  int j = 0;

  int tmp = 0;

  int k = 0;

  int b;

  int c;

  int * plain = new int[p.length()];

  string plainT;

  for (int r = 0; r < p.length(); r++) {

      i = (i + 1) % 256;

      j = (j + s1[i]) % 256;

      b = s1[i];

      s1[i] = s1[j];

      s1[j] = b;

      tmp = (s1[i] + s1[j]) % 256;

      k = s1[tmp];

      c = ((int)p[r] ^ k);

      plain[r] = c;

      plainT += (char)plain[r];

  }

  return plainT;

}  

string encrypt(vector<int>s1, vector<int> t1, string p) {

  int i = 0;

  int j = 0;

  int tmp = 0;

  int k = 0;

  int b;

  int c;

  int * cipher = new int [p.length()];

  string cipherT;

  cout << "Keys Generated for plaintext: ";

  for (int r = 0; r < p.length(); r++) {

      i = (i + 1) % 256;

      j = (j + s1[i]) % 256;

      b = s1[i];

      s1[i] = s1[j];

      s1[j] = b;

      tmp = (s1[i] + s1[j]) % 256;

      k = s1[tmp];

      cout << k << " ";

      c = ((int)p[r] ^ k);

      cipher[r] = c;  

      cipherT += (char)cipher[r];

  }

  cout << endl;

  return cipherT;

}

vector<int> permute(vector<int> s1, vector<int> t1) {

  int j = 0;

  int tmp;

  for (int i = 0; i< 256; i++) {

      j = (j + s1[i] + t1[i]) % 256;

      tmp = s1[i];

      s1[i] = s1[j];

      s1[j] = tmp;

  }

  return s1;

}

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3 years ago
Source view shows your website_____ A) exactly as it would appear when published B) approximately as it would appear when publis
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In html code so the answer is d
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3 years ago
Read 2 more answers
Create a text file named employee.dat containing the following data: b. Write a C++ program to read the employee.dat file create
Paul [167]

Answer:

1000 500 250 125 the output

Explanation:

write a program using integers userNum and x as input,  userNum divided by

x four times.  EX : If  the input is 2000 2 the output is 1000 500 250 125

8 0
3 years ago
Can someone help me with this project im confused
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u have to progrem a math algorithum

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