Answer:
123.2 L
Explanation:
We must first put down the required reaction equation;
6CO2(g) + 6H2O(g) ------> C6H12O6(g) + 6O2(g)
We know that 1 mol of a gas contains 22.4 L
hence the number of moles of carbon dioxide is obtained from;
1 mol = 22.4 L
x mol = 738 L
x = 738/22.4 = 32.9 mols
For water;
1 mol = 22.4 L
x mol = 792 L
x = 792/22.4
x = 35.4 mol
We obtain the limiting reactant;
6 mols of CO2 = 1 mole of glucose
32.9 mols of CO2 = 32.9 * 1/6 = 5.5 moles of glucose
For water;
6 mols of water yields 1 mol of glucose
35.4 mol of water yields 35.4 * 1/6 = 5.9 moles of glucose
CO2 is the limiting reactant
1 mol = 22.4 L
5.5 mol = 5.5 * 22.4 = 123.2 L
