Answer:
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
Explanation:
From the law of equilibrium, ΣF = 0 and ΣM = 0.
Let R be the reaction at the knife edge. Since the weight of the rod and zinc load act downward, and we take downward position as negative
-32 N - 2 N + R = 0
-34 N = -R
R = 34 N
Also, let us assume the knife-edge is x cm from the zero mark. Taking moments about the weight and assuming the knife-edge is right of the weight of the rod. Taking clockwise moments as positive and anti-clockwise moments as negative,
-(45 - 25)2 + (x - 45)R = 0
-(20)2 + (x - 45)34 = 0
-40 = -(x - 45)34
x - 45 = 40/34
x - 45 = 1.18
x = 45 + 1.18
x = 46.18 cm
x ≅ 46.2 cm
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
Given the following choices;
A) less than your true weight, mg.
B) equal to your true weight, mg.
C) more than your true weight, mg.
D) could be more or less than your true weight, mg, depending on the value of the speed.
The answer is; C
This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.
Momentum has a magnitude and a direction.
Its magnitude is (mass) x (magnitude of the velocity)
Its direction is the same as the direction of the velocity.
The thing you should memorize is: Momentum = (mass) x (velocity). P=mv
The crate is in equilibrium. Newton's second law gives
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
where
• <em>n</em> = magnitude of the normal force
• <em>mg</em> = weight of the crate
• <em>p</em> = mag. of push exerted by movers
• <em>f</em> = mag. of kinetic friciton, with <em>f</em> = 0.60<em>n</em>
<em />
It follows that
<em>p</em> = <em>f</em> = 0.60<em>mg</em> = 0.60 (43.0 kg) <em>g</em> = 252.84 N
so that the movers perform
<em>W</em> = <em>p</em> (10.4 m) ≈ 2600 J
of work on the crate. (The <em>total</em> work done on the crate, on the other hand, is zero because the net force on the crate is zero.)
Answer: <u><em>2.03259656 × 10^8</em></u>
Explanation:
1.5 x 10 = 15
√(15) = <em>3.87</em>
<u><em>put this to the side until we sum everything up..</em></u>
3.5 × 10 = 35
35 ^ 5 = <em>52521875</em>
So, now lets sum it all up....
(3.87) x (52521875) = <u><em>203259656.25</em></u>
but in scientific notation it is: <u><em>2.03259656 × 10^8</em></u>
<u><em>If helpful, please mark as brainliest! =)</em></u>