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saw5 [17]
2 years ago
6

You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.

Physics
2 answers:
tatyana61 [14]2 years ago
8 0

Given the following choices;

A) less than your true weight, mg.

B) equal to your true weight, mg.

C) more than your true weight, mg.

D) could be more or less than your true weight, mg, depending on the value of the speed.

The answer is; C

This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.  

Andreyy892 years ago
4 0

Answer:

C) more than your true weight, mg.

Explanation:

To understand this exercise, we propose that two vertical forces act, the first is the gravitational force Fg and the other is the normal force N, which is defined as the apparent weight that will mark the balance. If the force is equal to:

F = mxa

Where:

F: force (N)

m: mass (kg)

a: acceleration (m / s²)

And the gravitational force is equal to:

Fg = mxg

The normal force N shown by the balance is given by the following considerations (positive up and negative down), as follows:

N - Fg = mxa

Substituting the equation of Fg:

N - mxg = mxa

Clearing the normal force N:

N = mx (a + g)

From this equation it is concluded that if the elevator goes up, the acceleration value "a" will be positive. In this way, when the elevator goes up, the balance marks a greater value.

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A ball of mass m is thrown straight upward from ground level at speed v0. At the same instant, at a distance D above the ground,
n200080 [17]

Answer:

a. t = \frac{v_{0}  +/- \sqrt{v_{0} ^{2} - gD} }{g}  b. D = v₀²/2g

Explanation:

Here is the complete question

A ball is thrown straight up from the ground with speed v₀ . At the same instant, a second ball is dropped from rest from a height D , directly above the point where the first ball was thrown upward. There is no air resistance

Find the time at which the two balls collide.

Express your answer in terms of the variables D ,v₀ , and appropriate constants..

t = ?!

Part B

Find the value of D in terms of v₀ and g so that at the instant when the balls collide, the first ball is at the highest point of its motion.

Express your answer in terms of the variables v₀ and g .

D =?!

Solution

The distance moved by the ball dropped from distance,D with velocity v₀, H₁ = D - (v₀t - gt²/2) = D + v₀t + gt²/2.

The distance moved by the ball thrown straight upward with velocity v₀ is H₂ = v₀t - gt²/2.

The two balls collide when their vertical distances are equal. That is H₁ = H₂

So, D - v₀t + gt²/2 = v₀t - gt²/2

Collecting like terms

D + gt²/2 + gt²/2 = v₀t + v₀t

D +gt² = 2v₀t

gt² - 2v₀t + D = 0.

Using the quadratic formula,

t = \frac{-(-2v_{0} ) +/- \sqrt{(-2v_{0} )^{2} - 4 X g XD} }{2g} = \frac{2v_{0}  +/- \sqrt{4v_{0} ^{2} - 4gD} }{2g} = \frac{v_{0}  +/- \sqrt{v_{0} ^{2} - gD} }{g}

B. At its highest point, the velocity of the first ball, v = 0. Using v² = u² - 2gs where s = highest point of first ball when they collide and u = v₀.

0 = v₀² - 2gs

s = v₀²/2g.

Also, the time it takes the first ball to reach its highest point is gotten from v = u - gt. At highest point, v = 0 and u = v₀. So,

 0 = v₀ - gt₀

t₀ = v₀/g

Also H = s₁ + s where s₁  = distance moved by second ball in time t₀ for collision = v₀t₀ - gt₀²/2.

So, H = v₀t₀ - gt₀²/2 + v₀²/2g = v₀(v₀/g) - g(v₀/g)²/2 + v₀²/2g = v₀²/2g - v₀²/2g + v₀²/2g = v₀²/2g

6 0
3 years ago
Dos bolas, de masas mA = 40 g y mB =60 g, esta?n suspendidas como se observa en la figura. La bola ma?s ligera se jala en un a?n
Ymorist [56]
MA=40 or something I really don’t know
3 0
2 years ago
What type of electromagnetic waves do heat lamps give off?
Nitella [24]
Microwaves c…………….nnsjksisisysgxgd
7 0
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Read 2 more answers
B. How can you tell where sugar enters the blood?
Korolek [52]

Answer:

Sugar can’t enter cells directly

Explanation:

So when blood sugar level rises, cells in the pancreas signal for the release of insulin into the bloodstream. The insulin attaches to the sugars and signals cells to let it enter with the attached sugar. Insulin is known as the key that unlocks cells.

I hope I helped

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Where is a trench most likely to occur?
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D. convergent plate boundary involving an oceanic plate
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