Answer:
See below
Explanation:
When the spring is maximally compressed or stretched it exerts the most force ... then since F = m a aceleration is maximum at these points
Given
<span>u→Initial velocity of the spaceship=58<span>ms</span></span>
<span>v→after t= 12s ,Final velocity of the spaceship =153<span>ms</span></span>
The spaceship moving with uniform acceleration
<span><span>s→The distance covered in t s=<span>12</span><span>(u+v)</span>×t=<span>12</span><span>(58+153)</span>×12</span><span>=1266<span>m</span></span></span>
Answer:
You add up all the individual resistances of the resistors in the series circuit to get the total resistance of the circuit
Explanation:
A series circuit is a circuit that has most of its components connected end-to-end
following what was stated above, in a series circuit, the resistors are connected end to end. This means that the current that flows out from one of the resistors flows into the next one. As a result of this, the current through all the resistors is the same.
To get the total equivalent resistance in a series circuit, you add up all the individual resistances of the resistors in the series circuit. This should give you the total resistance in the circuit.
i.e
Total resistance = R1 + R2 + R3 ....
Answer:
Explanation:
Let the height of the tree is y and the distance of tree from point B is x.
According to the diagram
![tan61 = \frac{y}{x}](https://tex.z-dn.net/?f=tan61%20%3D%20%5Cfrac%7By%7D%7Bx%7D)
x = 0.55 y ..... (1)
![tan49.5 = \frac{y}{50+x}](https://tex.z-dn.net/?f=tan49.5%20%3D%20%5Cfrac%7By%7D%7B50%2Bx%7D)
(50 + 0.55y) 1.17 = y ..... from equation (1)
58.5 + 0.644 y = y
0.356 y = 58.5
y = 164.3 ft
Answer:
greatest speed=0.99c
least speed=0.283c
Explanation:
To solve this problem, we have to go to frame of center of mass.
Total available energy fo π + and π - mesons will be difference in their rest energy:
![E_{0,K_{0} }-2E_{0,\pi } =497Mev-2*139.5Mev\\](https://tex.z-dn.net/?f=E_%7B0%2CK_%7B0%7D%20%7D-2E_%7B0%2C%5Cpi%20%7D%20%20%3D497Mev-2%2A139.5Mev%5C%5C)
=218 Mev
now we have to assume that both meson have same kinetic energy so each will have K=109 Mev from following equation for kinetic energy we have,
K=(γ-1)![E_{0,\pi }](https://tex.z-dn.net/?f=E_%7B0%2C%5Cpi%20%7D)
![K=E_{0,\pi}(\frac{1}{\sqrt{1-\beta ^{2} } } -1)\\\frac{1}\sqrt{1-\beta ^{2} }}=\frac{K}{E_{0,\pi}}+1\\ {1-\beta ^{2}=\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta ^{2}=1-\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta = +-\sqrt{\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\\\\beta =+-\sqrt{1-\frac{1}{(\frac{109Mev}{139.5Mev+1)^2}}](https://tex.z-dn.net/?f=K%3DE_%7B0%2C%5Cpi%7D%28%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cbeta%20%5E%7B2%7D%20%7D%20%7D%20-1%29%5C%5C%5Cfrac%7B1%7D%5Csqrt%7B1-%5Cbeta%20%5E%7B2%7D%20%7D%7D%3D%5Cfrac%7BK%7D%7BE_%7B0%2C%5Cpi%7D%7D%2B1%5C%5C%20%20%20%7B1-%5Cbeta%20%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B%28%5Cfrac%7BK%7D%7BE_%7B0%2C%5Cpi%7D%7D%2B1%29%5E2%7D%7D%5C%5C%5Cbeta%20%5E%7B2%7D%3D1-%5Cfrac%7B1%7D%7B%28%5Cfrac%7BK%7D%7BE_%7B0%2C%5Cpi%7D%7D%2B1%29%5E2%7D%7D%5C%5C%5Cbeta%20%3D%20%2B-%5Csqrt%7B%5Cfrac%7B1%7D%7B%28%5Cfrac%7BK%7D%7BE_%7B0%2C%5Cpi%7D%7D%2B1%29%5E2%7D%7D%5C%5C%5C%5C%5C%5Cbeta%20%3D%2B-%5Csqrt%7B1-%5Cfrac%7B1%7D%7B%28%5Cfrac%7B109Mev%7D%7B139.5Mev%2B1%29%5E2%7D%7D)
![u'=+-0.283c](https://tex.z-dn.net/?f=u%27%3D%2B-0.283c)
note +-=±
To find speed least and greatest speed of meson we would use relativistic velocity addition equations:
![u=\frac{u'+v}{1+\frac{v}{c^{2} } } u'\\u_{max} =\frac{u'_{+} +v_{} }{1+\frac{v}{c^{2} } } u'_{+} \\u_{max} =\frac{0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } 0.828\\ u_{max} =0.99c\\u_{min} =\frac{u'_{-} +v_{} }{1+\frac{v}{c^{2} } } u'_{-}\\u_{min} =\frac{-0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } -0.828c\\u_{min} =0.283c](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bu%27%2Bv%7D%7B1%2B%5Cfrac%7Bv%7D%7Bc%5E%7B2%7D%20%7D%20%7D%20u%27%5C%5Cu_%7Bmax%7D%20%3D%5Cfrac%7Bu%27_%7B%2B%7D%20%2Bv_%7B%7D%20%7D%7B1%2B%5Cfrac%7Bv%7D%7Bc%5E%7B2%7D%20%7D%20%7D%20u%27_%7B%2B%7D%20%5C%5Cu_%7Bmax%7D%20%3D%5Cfrac%7B0.828c%20%2B0.9c%20%7D%7B1%2B%5Cfrac%7B0.9c%7D%7Bc%5E%7B2%7D%20%7D%20%7D%200.828%5C%5C%20u_%7Bmax%7D%20%3D0.99c%5C%5Cu_%7Bmin%7D%20%3D%5Cfrac%7Bu%27_%7B-%7D%20%2Bv_%7B%7D%20%7D%7B1%2B%5Cfrac%7Bv%7D%7Bc%5E%7B2%7D%20%7D%20%7D%20u%27_%7B-%7D%5C%5Cu_%7Bmin%7D%20%3D%5Cfrac%7B-0.828c%20%2B0.9c%20%7D%7B1%2B%5Cfrac%7B0.9c%7D%7Bc%5E%7B2%7D%20%7D%20%7D%20-0.828c%5C%5Cu_%7Bmin%7D%20%3D0.283c)