Answer:
The voltage that must be supplied is
V=1750volts
Explanation:
Step one :
The formula for the electric field between the charges is given by
E=V/d
Where E= the electric field
V= voltage or potential difference
d= the distance between the two electrodes
Step two :
Given that
E=3.5*0^6v/m
d=0.05cm to meter we have 0.0005m
V= unknown
By making v subject of formula we can solve for the required voltage
V=d*E
V=0.0005*3.5*10^6
V=1750volts
Answer:
The bicycle slows down because of the frictional force acting on the tyres of the bicycle. When this frictional force overcomes the force applied by paddling, the bicycle stops.
Please don't use a car's ignition coil as an example. Let's just say it's an ordinary transformer. If you connect 1800 volts AC to one side of the transformer and you get 12 volts out of the other side, then the turns of wire are in the same ratio as the voltages ... 1800/12 = 150.
A car coil doesn't work like an ordinary transformer. In a car, you put 12-volt pulses into one side, and you get voltage out of the other side that's high enough to fire spark plugs and ignite gasoline.
So you've actually got the primary and secondary windings labeled in reverse in the question, and you're actually using it as a step-DOWN transformer.
Answer:
L' = 1.231L
Explanation:
The transmission coefficient, in a tunneling process in which an electron is involved, can be approximated to the following expression:
L: width of the barrier
C: constant that includes particle energy and barrier height
You have that the transmission coefficient for a specific value of L is T = 0.050. Furthermore, you have that for a new value of the width of the barrier, let's say, L', the value of the transmission coefficient is T'=0.025.
To find the new value of the L' you can write down both situation for T and T', as in the following:
Next, by properties of logarithms, you can apply Ln to both equations (1) and (2):
Next, you divide the equation (3) into (4), and finally, you solve for L':
hence, when the trnasmission coeeficient has changes to a values of 0.025, the new width of the barrier L' is 1.231 L