3 years ago

8N4550oGoand the resultant of the systemEul22

Physics

1 answer:

murzikaleks [220]3 years ago

5 0

Answer:

what are u saying like where is the questions

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The high-speed winds around a tornado can drive projectiles into trees, building walls, and even metal traffic signs. In a labor

Travka [436]

Answer:

F = 183.153 N

Explanation:

given,

mass of the toothpick = 0.12 g = 0.00012 kg

initial velocity = 227 m/s

final velocity = 0 m/s

penetration depth = 16 mm = 0.016 m

using the equation of motion

v² - u² = 2 a s

0 - u² = 2 a s

- 221² = 2 × a × 0.016

a = 1526281.25 m/s²

Force is equal to

F = m a

= 0.00012 × 1526281.25

F = 183.153 N

3 0

3 years ago

A particle moves along the curve below. y = sqrt(1 + x^3) As it reaches the point (2, 3), the y-coordinate is increasing at a ra

blagie [28]

Answer:7 cm/s

Explanation:

Given

Particle move along curve

$y=\sqrt{1+x^3}$

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s

Differentiating y w.r.t time

$\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3x^2}{2\sqrt{1+x^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

Now at (2,3)

$\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3\cdot 2^2}{2\sqrt{1+2^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

$14=\frac{3\times 4}{2\times \sqrt{9}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{\mathrm{d} x}{\mathrm{d} t}=7 cm/s$

7 0

2 years ago

A stone is dropped off a cliff. After this stone has traveled a distance d . A second stone is dropped. the distance between the

Sladkaya [172]

Answer:

the same stones distance will be condtant .

so option no E

7 0

2 years ago

Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your f

Paul [167]

Answer:

Explanation:

lesgse in no

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2 years ago

If a moving car speeds up until it is going twice as fast, how much kinetic energy doe s it have compared with its initial kinet

dezoksy [38]

The kinetic energy of an object of mass m and velocity v is given by
$K= \frac{1}{2} mv^2$

Let's call $v_i$ the initial speed of the car, so that its initial kinetic energy is
$K_i = \frac{1}{2} mv_i^2$
where m is the mass of the car.

The problem says that the car speeds up until its velocity is twice the original one, so
$v_f = 2 v_i$
and by using the new velocity we can calculate the final kinetic energy of the car
$K_f = \frac{1}{2} mv_f^2 = \frac{1}{2}m (2 v_i)^2 = 4 ( \frac{1}{2} mv_i^2)=4 K_i$
so, if the velocity of the car is doubled, the new kinetic energy is 4 times the initial kinetic energy.

6 0

3 years ago

8N4550oGoand the resultant of the systemEul22​

8N4550oGoand the resultant of the systemEul22