6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
Answer:
A) 
B) 
C) for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
Step-by-step explanation:
A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below
if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be : 
strings
therefore for n ≥ 2
The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os
b ) The initial conditions
The initial conditions are :
C) The number of bit strings of length seven containing two consecutive 0s
here we apply the re occurrence relation and the initial conditions
for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
Answer:
Distributive property
Step-by-step explanation:
-3/4*5/4-(-6/7)*(-3/4)
-15/16-(18/28)
-15*7-18*4/112
-105-72/112
-177/112
Answer:
the answer is ≊20.4 I think not 100% sure
Step-by-step explanation:
if right please mark this answer brainliest
Answer:
Step-by-step explanation:
Each signal unit cubes are 1 cm to each side
the dimensions of the large cube is 4 by 6 by 3 width height and depth
a) volume of the cube Vol = area of the base times height
area of the base = the width times the depth
Volume = Base Depth
= Width x Depth x Height
= 4 x 3 x 6
= 12 x 6
Vol = 72 cm ³
b ) the volume of the smaller cuboid has different dimensions
the smaller cube is 2 by 2 by 1 width height and depth
Volume = Base Depth
= Width x Depth x Heigh
= 2 x 2 x 1
Vol smaller cuboid = 4
How many smaller cubes can be made?
The obvious answer might be to straight up divide the large cube volume by the smaler cuboid volume. That might work IF all of the cuboid dimensions divide evenly into the cube dimensions.
Number of cuboid = Volume of the cube / Volume of the cuboid
= 72 / 4
= 18
Check this answer by dividing the dimension of the cube by the cuboid
4 by 6 by 3
2 by 2 by 1
(4/2) by (6/2) by (3/1)
2 by 3 by 3 = 2 x 3 x 3 = 18
