The distance around a circle is called
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Given that the volume of the aquarium is 20m^3.
Volume = Area of Base x height
Area of Base = Volume / height = 20/h
Given that the aquarium has a square base.
Area of square = l^2
Thus, the length of the base of the aquarium is
The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.
Thus, the total perimeter of the frame is given by
Area of the four side faces of the aquarium is 4 times the length of the base times the height =
Total area to be covered by grass is the base and the four side faces and is given by
Cost of the entire metal frame =
Cost of the entire grass =
Therefore, total cost in terms of the height, h, is given by
Volume = Area of Base x height
Area of Base = Volume / height = 20/h
Given that the aquarium has a square base.
Area of square = l^2
Thus, the length of the base of the aquarium is
The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.
Thus, the total perimeter of the frame is given by
Area of the four side faces of the aquarium is 4 times the length of the base times the height =
Total area to be covered by grass is the base and the four side faces and is given by
Cost of the entire metal frame =
Cost of the entire grass =
Therefore, total cost in terms of the height, h, is given by
The determined value of mean µ is 1.3 and variance σ² is 0.81.
What is mean and variance?
- A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
- The variance is calculated as the square root of the variance.
- We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.
The table is attached as an image for reference.
Mean µ = ∑X P(X)
µ = 1.3
Variance (σ² ) = ∑ X² P(X)- (µ)²
= 2.5-(1.3)²
(σ² ) = 0.81
The determined value of mean µ is 1.3 and variance σ² is 0.81.
Learn more about mean and variance here:
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