To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.
Here,
h = Depth average
= Density
Moreover,
Replacing,
Finally the force
Answer:
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)²)/r
= ((2³.14*50/14.3)²)/50
= 9.64 m/s²
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Explanation:
Answer:
5,970 N
Explanation:
m = 597 kg
a = 10 m/s^2
Plug those values into the following equation:
F = ma
F = (597 kg)(10 m/s^2)
F = 5,970 N
<span>First of all, the maximum speed occurs when the object passes through the
equilibrium position
The kinetic energy when the object has this max speed is
K= 1/2 * mass * (1.25 m/s)^2
The potential energy in the spring when the speed is equal to zero
U= 1/2 * k * xmax^2
The maximun force of the spring is
mass*acceleration = k*xmax
m * 6.89 m/s2 = k * xmax
xmax = 6.89* m / k
0.5 * m * 1.56 = 0.5 * k * xmax^2
</span>m * 1.56 = k * (<span>6.89* m / k )^2 </span>
<span>
1.56 m = 47.47 m^2 / k
m/k = 0.032862
period = 2 *pi*sqrt[m/k]
= 2 pi </span><span>sqrt [ </span><span>0.032862]
= 1.139 s
A fourth of the period elapses between the instants of max acceleration and maximum speed
= 1/4* period
= 1/4 * </span><span><span>1.139 s </span>
= 0.284s </span>
Answer:
2.064 N.m
Explanation:
Torque: This is the force that act on a system, which tends to cause rotation or twisting. The S.I unit of Torque is N.m
Torque is represented mathematically as,
T = F×d........................ Equation 1
Where T = Torque, F = Force, d = perpendicular distance.
Given: F = 4.8 N, d = 0.43 m.
Substitute into equation 1
T = 4.8×0.43
T = 2.064 N.m
Hence the Torque produced = 2.064 N.m
