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3 years ago

Lena helps a child who is choking on his food. Which reliable method prepared her for helping with this injury?

2 answers:

7 0

knowledge of first aid ... eg St John Ambulance, Red Cross etc. I think that everyone in a school should be taught First Aid.

Karolina [17]3 years ago

5 0

Answer:

Safety training classes for babysitting

Explanation:

Got it right on edge

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2. A person applies a force of 66 N to a fridge as they push it across the length of a standard tennis court. So far today, the

Lubov Fominskaja [6]

Answer:

$P=39.2205\, watt$

$E=374.948 \,cal$

Explanation:

Given that:

force applied, $F=66\,N$

displacement, $s=23.77\,m$ (length of a tennis court)

time taken for pushing, t = 40 s

Since, work is given by:

$W=F.s$

$W=66\times 23.77$

$W=1568.82\,J$

Now, power is given as:

$P=\frac{W}{t}$

$P=\frac{1568.82}{40}$

$P=39.2205 \,watt$

Calories consumed is:

$E= 1568.82\times 0.239$

$E=374.948\, cal$

3 0

3 years ago

How does the speed of the different molecules that make up the air depend on their masses?

koban [17]

Larger molecules will move slower and smaller molecules will move faster. Did this answer your question?

8 0

3 years ago

49. A block is pushed across a horizontal surface with a

nata0808 [166]

Answer:

(a) 37.5 kg

(b) 4

Explanation:

Force, F = 150 N

kinetic friction coefficient = 0.15

(a) acceleration, a = 2.53 m/s^2

According to the newton's second law

Net force = mass x acceleration

F - friction force = m a

150 - 0.15 x m g = m a

150 = m (2.53 + 0.15 x 9.8)

m = 37.5 kg

(b) As the block moves with the constant speed so the applied force becomes the friction force.

$F = \mu m g \\\\150 = \mu\times 37.5\\\\\mu = 4$

8 0

3 years ago

Formula of atmospheric pressure

Alik [6]

Answer:

$P_{h}$ = $P_{0} e$ $\frac{-mgh}{kT}$

Explanation:

8 0

2 years ago

A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration ?

Nataliya [291]

Answer:

$-3m {s}^{-2}$

Explanation:

The initial velocity, u, of the car=15m/s

The final velocity, v, of the car =0m/s

Time, t, taken for the car to come to a stop=5s

Acceleration is calculated by,

$a= \frac{v - u}{t}$

By substitution,

$a= \frac{0- 15}{5}$

$a= \frac{- 15}{5}$

$a = -3 {ms}^{ - 2}$

The negative sign implies that the car has decelerated.

5 0

3 years ago