3 years ago

Find the focus of the parabola whose vertex is at the origin and whose directrix is x = 3.

Mathematics

1 answer:

defon3 years ago

6 0

Answer:

Step-by-step explanation:

Vertex is halfway between focus and directrix, so focus is (-3,0).

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Which values are solutions to the any quality below check all that apply

Yuri [45]

Answer:

B, C, E, F

Step-by-step explanation:

x^2 >= 49

A. 6: 6^2 = 36 No

B. 20: 20^2 = 400 Yes

C. -7: (-7)^2 = 49 Yes

D. -5: (-5)^2 = 25 No

E. -16: (-16)^2 = 256 Yes

F. 7: 7^2 = 49 Yes

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3 years ago

Find the product (2z+9)(z-7)

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Answer:

2z^2-5z-63

Step-by-step explanation:

2z^2+9z-14z-63

2z^2-5z-63

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2 years ago

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3 years ago

In the diagram, the measure of angle 6 is 98°. A transversal intersects 2 lines to form 8 angles. Clockwise from top left, the a

ser-zykov [4K]

Answer: 82°

Step-by-step explanation:

6 = 98°

180° - 98° = 82°

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2 years ago

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The model represents x2 – 9x + 14.

Stels [109]

Factorize the quadratic trinomial $x^2 - 9x + 14$ by the rule:

$ax^2+bx+c=a(x-x_1)(x-x_2), \text{ where } x_1,\ x_2 \text{ are its roots. }$

1. Find the roots:

$D=(-9)^2-4\cdot 14=81-56=25,\ \sqrt{D}=5,\\ \\ x_1=\dfrac{9-5}{2}=2,\ x_2=\dfrac{9+5}{2}=7.$

2. Factorize the polynomial:

$x^2 - 9x + 14=(x-2)(x-7).$

3. Only factor x-2 is given in options, then the correct choice is B.

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3 years ago

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