Answer:
what does the photo look like
Explanation:
Explanation:
Involves combining of nuclei: Nuclear fusion
Nuclear fusion is a radioactive reaction in which small atomic nuclei combines into larger ones with the release of a large amount of energy. The energy released is used to furnish a series of chain reactions.
Produces dangerous radioactive waste: Nuclear fission
Nuclear fission is used in powering most nuclear power plants. The products of these reactions are radioactive in nature. They are very dangerous to human health and the environment at large.
Have high activation energies: Nuclear fusion
The activation energy is the energy barrier that must be overcome before a reaction starts. Nuclear fusion reactions require very high amount of energy input to overcome the activation needed to start the reaction.
Releases large amounts of energy: Nuclear reactions
Both nuclear fusion and fission releases large amount of energy.
Occurs in the stars: Nuclear fusion
Nuclear fusion occurs in stars and they involve the combination of atomic nuclei to form larger ones.
Drives chemical plants: Nuclear fission
Chemical plants uses electricity and nuclear power plants can produce electricity through nuclear fission.
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Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
<span>Missing question: The first-order rate
constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g) + O2(g) at 70°</span><span>C is 6.82×10−3 s−1. Suppose we start with 2.70×10−2 mol of
N2O5(g) in a volume of 1.8 L .
</span>c₀(N₂O₅) = 0,027 mol ÷ 1,8 L.<span>
c</span>₀(N₂O₅) =
0,015 mol/L.<span>
c(N</span>₂O₅) = 0,019 mol/ 1,8 L = 0,01055 mol/L.<span>
k = 6,82·10</span>⁻³ s⁻¹.<span>
ln c(N</span>₂O₅) =
ln c₀(N₂O₅) -
k·t.<span>
t = (ln c</span>₀(N₂O₅) - ln c(N₂O₅)) ÷ k.<span>
t = 0,35 ÷ 0,00682 s</span>⁻¹.<span>
t = 51 s = 0,86 min.</span>
