The distance between Dustin and the planet is larger than the distance between Barb and the planet
Explanation:
The magnitude of the gravitational force between each astronaut and the planet is given by
where
:
is the gravitational constant
M is the mass of the planet
m is the mass of the astronaut
r is the separation between the astronaut and the planet
In this problem, we have:
- The force of gravity between Dustin and the planet is 120,265 N
- The force of gravity between Barb and the planet is 354,999 N
We see that the force exerted by the Planet on Barb is much greater than the force exerted by the planet on Dustin. Assuming that the mass of Dustin and Barb is similar, then we can say that the magnitude of the force of gravity depends mainly on the distance:
And since the force is inversely proportional to the square of the distance, this means that the distance between Dustin and the planet is larger than the distance between Barb and the planet.
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Answer:
T = mgsinθ = 2300(9.8)sin26.0 = 9880.88 ≈ 9900 N
Explanation:
#1
As we know that energy of electromagnetic wave is given by
so here we know that penetrating power will directly depends on its energy and energy inversely depends on wavelength
So here we can say correct answer will be
C) The penetrating power decreases as the wavelength increases.
#2
Speed of sound is maximum in solids and minimum in gas
so here as ice melts into water the speed of sound must have to decrease
so correct answer will be
D) The speed of sound would decrease because sound travels faster through solids than liquids.
#3
mechanical waves required medium to travel while non mechanical waves do not require any medium to travel
so here correct answer will be
A) sound
Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
