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lisabon 2012 [21]
4 years ago
13

The (blank) is something that should be tested according to the comfort level of the golfer. a. GRIP b. PUTTING GREEN c. SAND TR

AP d. TEE
Physics
1 answer:
gulaghasi [49]4 years ago
4 0

Answer:  <em> a). Grip</em>

The grip is the important thing to be consider for golfer. It is the most fundamental important aspects to the game, because it provides the solid contact.

Applying the correct grip, results in better golf shots and an increased confidence to the golfer, to address the ball in the right direction.

Simply the grip is the pressure applied to the club with the hand such that the golfer feels comfortable to make a brilliant shot.



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What creates the changes in step 1,2,3 of the nitrogen cycle
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1-fixation ( Bacteria Converts nitrogen to ammonium so plants can use it )
2-nitrification ( bacteria changes ammonium to nitrates and plants )
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6 0
3 years ago
A manometer that is filled with water (rho=1000 kg/m3) is connected to a wind tunnel to measure the pressure inside the test sec
Anna [14]

To develop this problem it is necessary to apply the concepts performed to the absolute pressure based on the reference pressure (atmospheric) and the pressure that is generated due to the height of the column of the measured liquid.

In mathematical terms the previous concept can be expressed as

P_{abs} = P_{atm} -\rho gh

Where

P_{atm}=Atmospheric Pressure

\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as

h = 10*10^{-3}m

g = 9.8m/s

\rho_{water} = 1000kg/m^3

P_{atm} = 100kPa

Replacing we have then that

P_{abs} = P_{atm} -\rho gh

P_{abs} = 100 -(1000)(9.8)(10*10^{-3})

P_{abs} = 99.9019kPa

Therefore the absolute pressure in the test section is 99.9019kPa

6 0
3 years ago
A block of mass 1.3 kg is resting at the base of a frictionless ramp. A bullet of mass 50 g is traveling parallel to the ramp su
aleksandrvk [35]

Answer:

s = 2.65 m

Explanation:

given,

mass of block,M = 1.3 Kg

mass of bullet,m = 50 g = 0.05 Kg

speed of bullet,u  = 250 m/s

speed of bullet after collision,v = 100 m/s

distance traveled by the block = ?

Assuming the angle of inclination of ramp equal to 40°

calculating the speed of the block

using conservation of momentum

M u' + m u = m v + M v'

initial speed of the block is equal to zero

0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'

1.3 v' = 7.5

  v' = 5.77 m/s

now, calculation of acceleration

equation  the horizontal component

-mg sin θ = ma

  a = - g sin θ

  a = - 9.8 x sin 40°  

  a = -6.29 m/s²

using equation of motion for the calculation of distance moved by the block

v² = u² + 2 a s

0² = 5.77² + 2 x (-6.29) x s

12.58 s = 33.29

s = 2.65 m

hence, the distance moved by the block is equal to 2.65 m

3 0
3 years ago
Ok so if atoms cant touch then why can the average human experience touch
djyliett [7]
While we think and feel that we are touching, we actually are not(: It’s all an illusion made by the brain
5 0
3 years ago
Read 2 more answers
Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He
mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

  • mu+MU = mv+MV............ Equation 1

Where:

  • m = mass of the first skater
  • M = mass of the second skater
  • u = initial velocity of the first skater
  • U = initial velocity of the second skater
  • v = final velocity of the first skater
  • V = final velocity of the second skater.

make v the subject of the equation.

  • v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

  • m = 105 kg
  • u = -2 m/s
  • M = 71 kg
  • U = 5 m/s
  • V = -3.4 m/s.

Substitute these values into equation 2

  • v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
  • v = (-210+355+241.4)/105
  • v = 386.4/105
  • v = 3.68 m/s
  • v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0
2 years ago
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