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jek_recluse [69]
3 years ago
6

A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v. The gravitationa

l field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance
Physics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

Two stars, each of mass M, form a binary system. ... used is the distance between the centers of the planets; here that distance is 2R. ... r appears in the denominator of Newton's law of gravitation, the force of ... The orbital speed of a satellite orbiting the earth in a circular orbit at the ... is undergoing uniform circular motion?

Explanation:

Two stars, each of mass M, form a binary system. ... used is the distance between the centers of the planets; here that distance is 2R. ... r appears in the denominator of Newton's law of gravitation, the force of ... The orbital speed of a satellite orbiting the earth in a circular orbit at the ... is undergoing uniform circular motion?

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During the operation of a laser, as photons interacts with atoms inside the laser the photons _________.
Rashid [163]

are ejected as an avalnche from excited states

7 0
4 years ago
Choose the correct statement regarding projectile motion in the absence of air resistance. Assume the object is at sea level mov
pishuonlain [190]

Answer:

Explanation:

The magnitude of the acceleration in the x direction is always zero: TRUE.

At the apex, in the y direction the velocity is zero and the accelration is positive. TRUE.

At the apex, in the x direction, the velocity is zero and the acceleration is zero. FALSE. The accelration is zero, but the velocity is the same it had when it was shot.

The magnitude of the velocity in the y direction is always constant. FALSE, it's subject to gravity and it's velocity varies as v=v_0 - 9.81ms^{-2} t

At the apex, in the Y direction, the velocity is negative and the acceleration is zero. FALSE. Velocity is zero, Acceleration is 9.81 ms^{-2}, towards the negative y axis

7 0
3 years ago
The four living things seen here, dog, flower, algae, and bacteria, are all made of cells. A - C are multicellular, but D is uni
djverab [1.8K]
B) They are all made up of at least one cell
6 0
3 years ago
Read 2 more answers
The largest and the smallest balls used in the experiment are with diameter 9.52 mm, and 2.38 mm respectively. For a glycerin wi
svlad2 [7]

Answer

given,

largest diameter of  balls = 9.52 mm = 0.00476 m

                                 radius = 0.00476

smallest diameter of ball = 2.38 mm = 0.00238 m

                                 radius = 0.00119

viscosity = 1.5 Pa.s

density of the ball = 1.42 g/cm

F = 6\pi \eta r V_t

F = \dfrac{mv}{t}

F = \dfrac{\dfrac{4}{3}\pi\ r^3\times (\rho-\sigma) \times 0.99 V_T}{t}

6\pi \eta r V_t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{t}

t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{6\pi \eta r V_t}

t= \dfrac{0.22 r^2 (\rho-\sigma) }{\eta}

for small balls

t= \dfrac{0.22\times 0.00119^2 (1460-1300)}{1.5}

t = 0.033 ms

for larger ball

t= \dfrac{0.22\times 0.00476^2 (1460-1300)}{1.5}

t = 0.531 ms

6 0
4 years ago
The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?
shusha [124]

Answer:

The pressure increases by a factor 8

Explanation:

For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:

p_1 V_1 = p_2 V_2

where

p_1 is the initial pressure

p_2 is the final pressure

V_1 is the initial volume

V_2 is the final volume

For the gas in this problem, the volume is reduced from

V_1 = 4 L

to

V_2 = 0.5 L

so we can rewrite the equation as

\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8

this means that the pressure of the gas will increase by a factor 8.

5 0
4 years ago
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