Given the next quadratic function:

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:
Yes it does not, i want my free points
Answer:945
Step-by-step explanation:
Answer:
Undefined
Step-by-step explanation:
Answer:
53
Step-by-step explanation:
Use pemdas
Use P and do (2+2)
then E 2^3 to get 8
Now you have 9-4/4+8*5
Do M and D To get 9-1+45
Now add and subtract to get your answer