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2 years ago

Part

Mathematics

2 answers:

enyata [817]2 years ago

5 0

If you want them to pay an equal amount it’ll be 283.8 if you wanna multiply it’ll be 2,550

san4es73 [151]2 years ago

3 0

each will have to pay 425 dollars per week

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Together, teammates Pedro and Ricky got 2673 base hits last season. Pedro had 277 more hits than Ricky. How many hits did each

ioda

Answer:

Pedro got 1520 base hits and Ricky got 1243.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of base hits that Pedro got.

y is the number of base hits that Ricky got.

Pedro and Ricky got 2673 base hits last season.

This means that $x + y = 2763$

Pedro had 277 more hits than Ricky.

This means that $x = y + 277$

Replacing in the first equation

$x + y = 2763$

$y + 277 + y = 2763$

$2y = 2486$

$y = \frac{2486}{2}$

$y = 1243$

$x = y + 277 = 1243 + 277 = 1520$

Pedro got 1520 base hits and Ricky got 1243.

4 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago

If the numerator and the numerator of a fraction are subtracted 1, the resulting fraction is 2/3, if the resulting fraction is i

tino4ka555 [31]

Answer:

Simplify the expression.

Exact Form:

1 /2

Decimal Form:

0.5

8 0

2 years ago