-2x^2+5x-4=0 , find the discriminant
1 answer:
Answer:
The discriminant is -7
Step-by-step explanation:
The discriminant of a quadratic function/equation(ax^2+bx+c = 0) is calculated as:
Here
b is the co-efficient of x
a is the co-efficient of x^2
and c is the constant
Given equation is:
Here
a = -2
b = 5
c = -4
Putting the values in the formula for discriminant
As the discriminant is negative, the equation has no real solution.
Hence,
The discriminant is -7
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It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
