The balanced chemical reaction is:
<span>2 Al (s) + 3 Fe(NO3)2 (aq) = 3 Fe (s) + 2 Al(NO3)2 (aq)
</span>
The ratios or the coefficients between the reactants and the products will be used for further calculations.
305 g Fe(NO3)2 solution (.755) = 230.275 g <span>Fe(NO3)2
</span> 230.275 g Fe(NO3)2 ( 1mol / 179.87 g) ( 3 mol Fe / 3 mol <span>Fe(NO3)2) ( 55.85 g / mol) = 71.500 g Fe</span>
Answer:
0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)
Explanation:
Based on the reaction:
6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI
<em>6 moles of Na₂S₂O₃ react per mole of KIO₃</em>
Assuming the molarity of the KIO₃ solution is 0,1M:
Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = <em>5.0x10⁻⁴ moles</em>
As 6 moles of thiosulfate reacted per mole of iodate:
5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ / 1 mole KIO₃) =
<em>3.0x10⁻³ moles of Na₂S₂O₃. </em>In 6.5mL (6.5x10⁻³L):
3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃
Answer 12.2g is the answer
Answer:
The answer to your question is: density = 5 g/cm³
Explanation:
Data
Volume = v = 2 m³
mass = m = 1 x 10⁴ kg
Density = d = ? g/cm³
Formula
density = mass/volume
Volume
1 m³ ------------------- 1 000 000 cm³
2 m³ ------------------ x
x = (2 x 1 000 000) / 1
x = 2 000 000 cm³
Mass
1 kg ------------------ 1000 g
1 x 10⁴ kg ------------ x
x = (1 x 10⁴ x 1000) / 1
x = 10 000 000 g
density = (10 000 000) / 2 000 000
density = 5 g/cm³
