Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)
1 answer:
Answer:
The amount of NaOH required to prepare a solution of 2.5N NaOH.
The molecular mass of NaOH is 40.0g/mol.
Explanation:
Since,
NaOH has only one replaceable -OH group.
So, its acidity is one.
Hence,
The molecular mass of NaOH =its equivalent mass
Normality formula can be written as:
Substitute the given values in this formula to get the mass of NaOH required.
Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g
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Explanation:
Apply the mass of balance as follows.
Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank
[/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] =
+ h = 1
= 1 - h
= dt
= t + C
Given at t = 0 and V = 0
= 0
or, h = 0
-ln(1 - h) = t + C
Initial condition is -ln(1) = 0 + C
C = 0
So, -ln(1 - h) = t
or, t = ........... (1)
(a) Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.
t =
t =
=
= 0.916 seconds
(b) As maximum height of water level in the tank is achieved at steady state that is, t = .
1 - h = exp (-t)
1 - h = 0
h = 1
Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.
Answer: C) Both are made up of monomers that are linked by covalent bonds
Explanation: Polymers are large molecules which are formed by combination of small repeating units called as monomers.
Natural polymers are found in nature such as cellulose whereas synthetic polymers are synthesized in laboratories such as Nylon 6,6.
All the polymers, whether natural or synthetic are made up of monomers and are joined by covalent bonds.
