Let x= width
Then x+3= length
So 2x+2x+6=26
4x+20
x=5
Width is x=5m and length is x+3=8m
Area is (lenght)(width) so (5)(8)= 40m squared
F=R G=S H=T
FG≈RS GH≈ST FH≈RT
Count the number of zeros past the number 10. That is the value of M.
Let <em>n</em> be the smallest of the three numbers. Then
<em>n</em> + (<em>n</em> + 1) + (<em>n</em> + 2) = 5 ((<em>n</em> + 1) - 22)
Solve for <em>n</em> :
3<em>n</em> + 3 = 5 (<em>n</em> - 21)
3<em>n</em> + 3 = 5<em>n</em> - 105
2<em>n</em> = 108
<em>n</em> = 54
Then the three numbers are 54, 55, and 56.
Answer:
look on math papa
Step-by-step explanation:
