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3 years ago

1+1 I Will reward you wit 100 points

Mathematics

1 answer:

Ket [755]3 years ago

8 0

Answer:

2 lol

Step-by-step explanation:

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F(x) = -2x2 + 7<br> Find f(-5)

Ainat [17]

Answer:

f(-5) = -43

Step-by-step explanation:

Step 1: Define

f(x) = -2x² + 7

f(-5) is x = -5

Step 2: Substitute and Evaluate

f(-5) = -2(-5)² + 7

f(-5) = -2(25) + 7

f(-5) = -50 + 7

f(-5) = -43

5 0

4 years ago

Read 2 more answers

What's 8.23+10.9 simplified?

Serggg [28]

It is going to be 18.32

7 0

3 years ago

3(x + 2) - 6 = 15 please heelp

Alex

Answer:

Step-by-step explanation:

First multiply inside of the parenthesis with 3 then add the like terms

3x + 6 - 6 = 15 ➡ 3x = 15 divide both sides with 3 and x = 5

4 0

3 years ago

Add. 4.52 + 7.99 (Round your answer to the nearest tenth place

Sunny_sXe [5.5K]

Answer:

12.50

Step-by-step explanation:

4.52 is roundes to 4.50. Then, 7.99 is rounded to 8. Thus, 4.50 + 8 = 12.50

7 0

3 years ago

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

$P(B) = \frac{8}{12}$

$P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}$

<h3><u>Find </u><u> P(R | B)</u></h3><h3> $P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}$ </h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

$\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%$

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0

4 years ago