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nasty-shy [4]
2 years ago
7

A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s

top?​
Physics
1 answer:
Flura [38]2 years ago
7 0

Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

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The theorem is stated as E = mc^{2} where c is the velocity of light and m is the mass converted into energy.

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6 0
3 years ago
Read 2 more answers
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2 years ago
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Answer:

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