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nasty-shy [4]
3 years ago
7

A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s

top?​
Physics
1 answer:
Flura [38]3 years ago
7 0

Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

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Answer:

D. Electricity will flow if the electrons are bound loosely to their atoms in the material.

Explanation:

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Thus, the correction for this question is "D"

D. Electricity will flow if the electrons are bound loosely to their atoms in the material.

6 0
3 years ago
An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds. Which describes the acceleration? negati
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Answer:

we could use the formula, v=u+at,

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A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo
kiruha [24]

Answer:

The value is  V_{os} = 0.001 \  V

Explanation:

From the question we are told that

     The circuit resistance is  R_1 =  10 \ k \Omega

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Generally the offset voltage is mathematically reparented as

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=>        V_{os} = 10 *10^{3}*  100 *10^{-9}

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3 years ago
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Answer:

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(C)

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2 years ago
A police officer at rest at side of highway notices speeder moving at 62 km/h along road.when speeder passes ,officer accelerate
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To answer the following questions for this specific problem:

a. 11.48 secs

b. Vp = a*t*3.6 = 3*11.48*3.6 = 124.0 km/h

<span>c. 9.1 secs. </span>

I am hoping that this answer has satisfied your query about and it will be able to help you.

4 0
3 years ago
Read 2 more answers
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