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nasty-shy [4]
3 years ago
7

A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s

top?​
Physics
1 answer:
Flura [38]3 years ago
7 0

Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

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Energy slowly leaks outward through the diffusion of photons that repeatedly bounce off ions and electrons
stepan [7]

Energy slowly leaks outward through the radiative diffusion of photons that repeatedly bounce off ions and electrons.

<h3>What is radiative diffusion?</h3>

A radiation zone is a layer of a star's core where energy is mostly carried toward the outside by radiative diffusion and thermal conduction rather than convection.

As photons, energy passes through the radiation zone as electromagnetic radiation.

The radiative diffusion of photons that repeatedly bounce off ions and electrons progressively drains energy outward.

Hence,radiative diffusion is correct answer.

To learn more about radiative diffusion refer:

brainly.com/question/3598352

#SPJ4

7 0
2 years ago
The jet fuel in an airplane has a mass of 97.5 kg and a density of 0.804 g/cm3. What is the volume of this jet fuel
Mnenie [13.5K]

The volume of the jet fuel is 1.213 x 10⁵ cm³.

<h3>What is density?</h3>

Density is a physical property that measures the ratio of mass to volume occupied by an object.

Density = mass/volume

Volume = mass/density

<h3> Volume of the jet fuel</h3>

The volume of the jet fuel is calculated as follows;

Volume = (97500 g)/(0.804 g/cm³)

Volume = 1.213 x 10⁵ cm³

Thus, the volume of the jet fuel is 1.213 x 10⁵ cm³.

Learn more about volume here: brainly.com/question/1972490

5 0
2 years ago
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2
Vaselesa [24]

Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01

7 0
3 years ago
A horizontal force of 120N is required to push a block across a floor at constant velocity, what is the net force acting on the
Hitman42 [59]

Answer:

a horizontal force of 120N to Push the block into the floor is called net force

8 0
3 years ago
Mo Farah won the 10,000 meter race in the 2012 Olympics with an official time of 27 minutes, 30.42 s . To the correct number of
seropon [69]
Speed=distance/time
distance = 10,000 m
time= 27 min 30.42s but we need to convert that completely to seconds
(27x60)+30.42= 1650.12 rounded to 1650
speed=10,000/1650.12
speed=6.059063
Because when we do sig dig we round to the least number of digits we would round to 4 because 1650.12 gets rounded to 1650
so 6.059 m/s
4 0
2 years ago
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